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4 years ago

Help ASAP I'm bad at solving this I will give out 20 points!

Mathematics

1 answer:

nexus9112 [7]4 years ago

3 0

Answer:

(0,3/2), (0,2),(6,0),(9/4,0)

I hope it helpss..

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If f(x) = x2 + 4x - 12, find f(2).

Illusion [34]

Answer:

-3

Step-by-step explanation:

Please write this as f(x) = x^2 + 4x - 12. "x^2" represents "the square of x."

f(2) is the value of this function when x = 2:

f(2) = f(2) = (2)^2 + 4(2) - 12 = 9 - 12 = -3

7 0

3 years ago

Bo bought a few items for $93.84, not including tax. If the tax rate was 7%, what was the total cost of these items, including t

Nastasia [14]

Answer:

Total cost is $100.41 ( $93.84 + $6.57)

Step-by-step explanation:

Thinking Point: The total cost is the cost of the items PLUS the tax. 93.84 ∙ 0.07 = 6.5688 (round to “cents”) = $6.57

Hope this helped!

6 0

3 years ago

Read 2 more answers

Precalc experts! I need your help!

mars1129 [50]

Answer:

$f(x)\to 1$

Step-by-step explanation:

The function approaches its horizontal asymptote in both directions as the magnitude of x gets large. The limit is y = 1.

7 0

3 years ago

Diffrence of partial products and regrouping

Alex

Partial products is breaking down every number in multiplication and adding them. Regrouping is grouping number them adding them. They are different because one is taking all the numbers broken down, while the other is just a couple of the number.

8 0

3 years ago

A one-parameter family of solutions of the DE P' = P( 1 - P) is given below. P = c1et/1 + c1et Does any solution curve pass thro

topjm [15]

Answer:

a. The curve $P(t) = -\frac{6e^t}{5-6e^t}$ passes through the point (0, 6)

b. No solution of the curve $P(t)$ passes through the point (0, 1)

Step-by-step explanation:

Consider the family of the solution of DE $P' = P(1 - P)$ is $P = \frac{c_1e^t}{1 + c_1e^t}$

a. If any solution passes through the point (0, 6), then there is $c_1$ such that the point (0, 6) satisfies the solution $P = \frac{c_1e^t}{1 + c_1e^t}$

Substitute $t = 0, P = 6$ in $P = \frac{c_1e^t}{1 + c_1e^t}$ and then solve the equation to obtain $c_1$

$P(t) = \frac{c_1e^t}{1 + c_1e^t}\\P(0) = \frac{c_1e^0}{1+c_1e^0}\\ 6 = \frac{c_1}{1 + c_1}\\ c_1 = -\frac{6}{5}$

Therefore, the curve $P(t) = -\frac{6e^t}{5 - 6e^t}$ passes through the point (0, 6)

b. If any solution passes through the point(0, 1), then there is $c_1$ such that the point (0, 1) satisfies the solution $P = \frac{c_1e^t}{1+c_1e^t}$

$P(t) = \frac{c_1e^t}{1 + c_1e^t}\\ P(0) = \frac{c_1e^0}{1 + c_1e^0}\\ 1 = \frac{c_1}{1+c_1} \\1 + c_1 = c_1$

this is not possible

Hence, there is no curve $P(t)$ that exists which passes through the point (0, 1)

4 0

3 years ago