Question

For what value of x is (2x^2+8x)/(x+4)(x^2-9) undefined?

Answer 1

Answer:

The value at x =3 is undefined for the given expression

Step-by-step explanation:

Given expression is $\frac{2x^2+8x}{(x+4)(x^2-9)}$

To find for what value of x is undefined in the given expression :

$\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x(x+4)}{(x+4)(x^2-9)}$

$=\frac{2x}{x^2-9}$

$\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x}{x^2-9}$

If we put x=3 in the above expression we get

$\frac{2x}{x^2-9)}=\frac{2(3)}{3^2-9}$

$=\frac{6}{9-9}$

$=\frac{6}{0}$

Therefore $\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{6}{0}$

The value at x =3 is undefined for the given expression