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Norma-Jean [14]
3 years ago
9

Please please please no guessing I had to type this all out. How do oceanographers define saltanily?

Chemistry
1 answer:
Gre4nikov [31]3 years ago
5 0
The correct answer is D. Number of grams of salt per kilometer of water.
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As you move from left to right across the periodic table elements ?
Sidana [21]

Explanation:

Quite a number of properties varies across a period. Some remains constant whereas others decreases.

As one moves from left to right;

  • The energy level remains the same.
  • The ionization energy increases progressively as a result of increasing nuclear charge.
  • Electron affinity increases from left to right.
  • Electronegativity increases.
  • Electropositivity decreases.

learn more:

Periodic table brainly.com/question/2014634

#learnwithBrainly

6 0
3 years ago
For green plant cells, which are the substances that result from photosynthesis that are used in cellular respiration? A. oxygen
strojnjashka [21]

Answer:

B. oxygen and glucose

Explanation:

Oxygen for respiration and glucose for energy utilization

6 0
3 years ago
if the mass of 191 grams NaCl reacted with 74 frams of calcium hydroxide and 80 grams of sodium hydroxide is produced, what mass
nadya68 [22]
<h3>Answer:</h3>

110.98 g/mol

<h3>Explanation:</h3>

The reaction between NaCl and Ca(OH)₂ is given by the equation;

2NaCl(aq) + Ca(OH)₂(s) → 2NaOH(aq) + CaCl₂(aq)

We are required to determine the mass of CaCl₂ produced,

We will use the following simple steps;

Step 1: Moles of NaCl and Ca(OH)₂ given

Number of moles = Mass ÷ Molar mass

Moles of NaCl

Mass of NaCl = 191 g

Molar mass NaCl = 58.44 g/mol

Number of moles = 191 g ÷ 58.44 g/mol

                             = 3.268 moles

                             = 3.27 Moles

Moles of Ca(OH)₂

Mass of Ca(OH)₂ = 74 g

Molar mass of Ca(OH)₂ = 74.093 g/mol

Number of moles = 74 g ÷ 74.093 g/mol

                             = 0.998 mole

                              = 1.0 mole

However, from the equation  2 moles of NaCl requires 1 mole of Ca(OH)₂

Therefore, from the amount of reactants available NaCl was in excess and Ca(OH)₂ is the limiting reactant .

Step 2: Moles of CaCl₂ produced

From the equation

1 mole of Ca(OH)₂ reacts with NaCl to produce 1 mole of CaCl₂

Therefore; the mole ratio of Ca(OH)₂ to CaCl₂ is 1: 1

Thus;

Moles of CaCl₂ produced is 1.0 moles

Step 3: Mass of CaCl₂ produced

Moles of CaCl₂ = 1.0 mole

Molar mass CaCl₂ = 110.98 g/mol

But; mass = number of moles × Molar mass

Therefore;

Mass of CaCl₂ = 1.0 mole × 110.98 g/mol

                       = 110.98 g CaCl₂

3 0
3 years ago
How are oxidation-reduction reactions related to how you use energy?
Tems11 [23]

Answer:

In oxidation reduction reactions, one species gets reduced by taking on electron(s) and another species gets oxidized by losing electrons. They also flow by a wire

Explanation:

8 0
3 years ago
PLEASE HELPPPP! HOW DO I DO THIS???
kow [346]

Answer:

1552.83J Released

Explanation:

1. mass/m=225

Initial temp:86C, final:32.5C

Changed Temp: 32.5-86= -53.5C

s=0.129 J/gC

Formula: q= m times s times changed Temp.

q=(225)(0.129)(-53.5)

q= -1552.83 J

q=1552.83 J Released

8 0
3 years ago
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