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Wewaii [24]
3 years ago
7

What type of intermolecular forces are present in liquid methanol?

Chemistry
1 answer:
salantis [7]3 years ago
7 0

Answer:

Hydrogen bonds

Explanation:

Hydrogen bonds are bonds formed in polar molecules in which an hydrogen atom is directly joined to a highly electronegative atom such as oxygen or nitrogen or fluorine.

A hydrogen bond is just an electrostatic attraction between a hydrogen atom of one molecule and the electronegative atom of a neighboring molecule.

Methanol has a formula of CH₃OH and the hydrogen bond is between the H and O.

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Sue dissolved a certain amount of salt in 400 grams of water to obtain 405 grams of salt solution. What was the mass of the salt
harina [27]
<span>Sue added salt to water in order to make a salt solution, the original amount of water is 400 grams. In order for Sue to obtain 405 grams of salt solution using 400 grams of water, 5 grams of salt must be added.</span>
3 0
3 years ago
An 8.42 g piece of metal with a specific heat of 1.020 J g-1 k-1 wasn't heated to an unknown temperature. The metal was then pla
ANTONII [103]

Answer:

T = 61.344\,^{\textdegree}C

Explanation:

The heat received by water is equal to the heat rejected by the piece of metal. That is to say:

-Q_{piece} = Q_{water}

(8.42\,g) \cdot \left(1.020\,\frac{J}{g\cdot ^{\textdegree}C}  \right) \cdot (T - 20.40\,^{\textdegree}C)= (44.2\,g)\cdot \left(4.187\,\frac{J}{g\cdot ^{\textdegree}C} \right)\cdot (20.40\,^{\textdegree}C-18.50\,^{\textdegree}C)

\left(8.588\,\frac{J}{^{\textdegree}C} \right)\cdot (T-20.40\,^{\textdegree}C) = 351.624\,J

The initial temperature of the piece of metal is:

T = 61.344\,^{\textdegree}C

4 0
3 years ago
Read 2 more answers
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Luba_88 [7]
It would be a continuous straight line
6 0
3 years ago
Gaseous butane CH3CH22CH3 reacts with gaseous oxygen gas O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. What is
SOVA2 [1]

Answer:

10.56 g

Explanation:

C4H10(g) + 13/2O2 (g) -------> 4CO2(g) + 5H2O(l)

Number of moles of butane = 3.49g/ 58 g/mol = 0.06 moles

1 mole butane yields 4 moles of CO2

0.06 moles of butane = 0.06 × 4/1 = 0.24 moles of CO2

Number of moles of oxygen = 17.1g/32g/mol = 0.53 moles of oxygen

6.5 moles of oxygen yields 4 moles of CO2

0.53 moles of oxygen yields 0.53 × 4/6.5 =0.33 moles of CO2

Butane is the limiting reactant

Theoretical yield of CO2 = 0.24 moles × 44g/mol = 10.56 g

3 0
3 years ago
Which element has the larger Zell
Eddi Din [679]

Answer:

a

Explanation:

because of potassium and lithium belongs to

alkali metals

6 0
3 years ago
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