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never [62]
3 years ago
7

How many moles of hydrogen gas(H2) are needed to react with 15 moles of chlorine gas

Chemistry
1 answer:
NNADVOKAT [17]3 years ago
4 0

Answer:

15 moles of hydrogen gas are needed to react with 15 moles of chlorine gas.

Explanation:

The balanced reaction is:

H₂ (g) + Cl₂ (g) → 2 HCl (g)

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of the compounds participate in the reaction:

  • H₂: 1 mole
  • Cl₂: 1 mole
  • HCl: 2 moles

Then you can apply the following rule of three:  If 1 mole of Cl₂ reacts with 1 mole of H₂, 15 moles of Cl₂ with how many moles of H₂ does it react?

moles of H_{2} =\frac{15 moles of Cl_{2} *1mole of H_{2}}{1moles of Cl_{2}}

moles of H₂= 15

<u><em>15 moles of hydrogen gas are needed to react with 15 moles of chlorine gas.</em></u>

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The atmospheric pressure on the surface of Venus is 6.84X10^4. Calculate the atmospheric pressure in atm and torr. Round each of
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Answer:

0.675 atm

513 Torr

Explanation:

Given is that, the atmospheric pressure on the surface of Venus is

6.84 X 10⁴ Pa.

1 atm (atmospheric pressure) is equal to 101325 pascal (Pa).

To convert divide the pressure value by 101325.

Pressure in atm = \frac{6.84 \times 10^{4} }{101325}

= 0.675055 atm

Rounding it off to 3 significant digits: 0.675 atm

Now,  one Torr is 133.322 Pa. For conversion, divide the pressure value by 133.322.

Pressure in Torr = \frac{6.84 \times 10^{4} }{133.322}

=513.04219 Torr

Rounding it off to 3 significant digits: 513 Torr

5 0
3 years ago
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It expresses a cube using cm
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3 years ago
f 23.6 mL of 0.200 M NaOH is required to neutralize 10.00 mL of a H3PO4 solution , what is the concentration of the phosphoric a
Eduardwww [97]

Answer:

Explanation:

H3PO4(aq) + 3NaOH(aq) → Na3PO4(aq) + 3H2O(l)

mole of NaOH = 23.6 * 10 ⁻³L * 0.2M

= 0.00472mole

let x be the no of mole of H3PO4 required of  0.00472mole of NaOH

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cross multiply

3x = 0.0472

x = 0.00157mole

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= 0.00157mole / (10*10⁻³l)

= 0.157M

<h3>The concentration of unknown phosphoric acid is  0.157M</h3>
7 0
2 years ago
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A 1.26 m aqueous solution of an ionic compound with the formula mx2 has a boiling point of 101.63 ∘c. part a calculate the van't
12345 [234]

<span>Answer is: Van't Hoff factor (i) for this solution is 1.051 .
Change in boiling point from pure solvent to solution: ΔT =i · Kb · b.
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b -  molality, moles of solute per kilogram of solvent.
b = 1.26 m.
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i = 1.63°C ÷ (0.512°C/m · 1.26 m).

i = 1.051.

5 0
3 years ago
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Answer:

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