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2 years ago

How many moles of hydrogen gas(H2) are needed to react with 15 moles of chlorine gas

Chemistry

1 answer:

NNADVOKAT [17]2 years ago

4 0

Answer:

15 moles of hydrogen gas are needed to react with 15 moles of chlorine gas.

Explanation:

The balanced reaction is:

H₂ (g) + Cl₂ (g) → 2 HCl (g)

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of the compounds participate in the reaction:

H₂: 1 mole
Cl₂: 1 mole
HCl: 2 moles

Then you can apply the following rule of three: If 1 mole of Cl₂ reacts with 1 mole of H₂, 15 moles of Cl₂ with how many moles of H₂ does it react?

$moles of H_{2} =\frac{15 moles of Cl_{2} *1mole of H_{2}}{1moles of Cl_{2}}$

moles of H₂= 15

<u><em>15 moles of hydrogen gas are needed to react with 15 moles of chlorine gas.</em></u>

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A mixture with H2 and He exerts a total pressure of 0.48 atm. If there is 1.0 g of H2 and 1.0 g of He in the mixture, what is th

lara [203]

Answer is: the partial pressure of the helium gas is 0.158 atm.

p(mixture) = 0.48 atm; total pressure.

m(H₂) = 1.0 g; mass of hydrogen gas.

n(H₂) = m(H₂) ÷ M(H₂).

n(H₂) = 1.0 g ÷ 2 g/mol.

n(H₂) = 0.5 mol; amount of hydrogen.

m(He) = 1.0 g; mass of helium.

n(He) = 1 g ÷ 4 g/mol.

n(He) = 0.25 mol; amount of helium.

χ(H₂) = 0.5 mol ÷ 0.75 mol.

χ(H₂) = 0.67; mole fraction of hydrogen.

χ(He) = 0.25 mol ÷ 0.75 mol.

χ(He) = 0.33; mole fraction of helium.

p(He) = 0.33 · 0.48 atm.

p(He) = 0.158 atm; the partial pressure of the helium gas.

8 0

2 years ago

The total mass of reactants and products is _______ during a chemical reaction

SIZIF [17.4K]

Answer: The total mass of reactants and products is the same during a chemical reaction.

Explanation:

the total mass of reactants is equal to the total mass of products.

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2 years ago

what are the relative strengths of intermolecular forces compared to the forces between ions in a salt or the forces between met

Sophie [7]

There are two kinds of forces, or attractions, that operate in a molecule—intramolecularand intermolecular. Let's try to understand this difference through the following example.

Figure of towels sewn and Velcroed representing bonds between hydrogen and chlorine atoms

We have six towels—three are purple in color, labeled hydrogen and three are pink in color, labeled chlorine. We are given a sewing needle and black thread to sew one hydrogen towel to one chlorine towel. After sewing, we now have three pairs of towels: hydrogen sewed to chlorine. The next step is to attach these three pairs of towels to each other. For this we use Velcro as shown above.

So, the result of this exercise is that we have six towels attached to each other through thread and Velcro. Now if I ask you to pull this assembly from both ends, what do you think will happen? The Velcro junctions will fall apart while the sewed junctions will stay as is. The attachment created by Velcro is much weaker than the attachment created by the thread that we used to sew the pairs of towels together. A slight force applied to either end of the towels can easily bring apart the Velcro junctions without tearing apart the sewed junctions.

Exactly the same situation exists in molecules. Just imagine the towels to be real atoms, such as hydrogen and chlorine. These two atoms are bound to each other through a polar covalent bond—analogous to the thread. Each hydrogen chloride molecule in turn is bonded to the neighboring hydrogen chloride molecule through a dipole-dipole attraction—analogous to Velcro. We’ll talk about dipole-dipole interactions in detail a bit later. The polar covalent bond is much stronger in strength than the dipole-dipole interaction. The former is termed an intramolecular attraction while the latter is termed an intermolecular attraction.

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2 years ago

A strong electrolyte is one that ________ completely in solution. a) reacts.b) decomposes.c) disappears.d) ionizes.

raketka [301]

Answer:

Explanation:

elctrolytes decomposes

3 0

2 years ago

Read 2 more answers

Which of the following results in an increase in the entropy? (4 points)

Dima020 [189]

Dissolving sugar in water results in an increase in the entropy.

Hence, Option (D) is correct answer.

<h3>What is Entropy ?</h3>

Measurement of randomness of a system is called entropy. It is an extensive property. It is a state function. Unit of entropy is JK⁻¹ mol⁻¹.

Now lets check all options one by one

Option (A): Freezing water

Freezing water decreases the entropy because here second law of thermodynamics does not violate.

So it is incorrect option

Option (B): Cooling water

Cooling water does not increases entropy because entropy increases when solid melts to give liquid.

So it is incorrect option

Option (C): Condensing water vapour

In Condensing water vapour the temperature of liquid phase decreases and thus kinetic energy decreases. The randomness will decrease and hence entropy will also decrease.

So it is incorrect option.

Option (D): Dissolving sugar in solute

In dissolving sugar in solute the solid dissociates to ions and the randomness will increase and hence entropy will also increase.

So it is correct option

Thus from the above conclusion we can say that Dissolving sugar in water results in an increase in the entropy.

Hence, Option (D) is correct answer.

Learn more about the Entropy here: brainly.com/question/1477087

#SPJ1

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1 year ago