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4 years ago

Brianna's age is 4 years less than 3 times Stephanie's age. The sum of their ages is 28

Mathematics

1 answer:

Reil [10]4 years ago

8 0

What's the question??

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Below is an archery target and the rules for scoring. Three arrows were shot and landed on the points (-5,4), (-8,7), and (1,6).

dezoksy [38]

Answer:

15 in your answer

Step-by-step explanation:

-5 +-8 = -13

4+7+1+6=18

-13+18=15

7 0

3 years ago

Read 2 more answers

Help I'm so confused

pshichka [43]

z = -11

2.4-4.6=0.2z

-2.2 = 0.2z

-2.2/0.2=z

-11=z

z=-11

3 0

3 years ago

I need a lot of help with this question!!!!!! CLICK THE PICTURE

malfutka [58]

I need a lot of help with this question!!!!!!

CLICK THE PICTURE

The x is going to =7.5 i belive is right

8 0

3 years ago

What number is the missing numerator? 16,16,2

Lelu [443]

Here is your answer:

Your answer is 8:

Reason:

8÷2=16
16÷8=2

Which makes 8 your answer.

Hopes this Helps!

8 0

3 years ago

The table shows a proportional relationship between the number of pounds of bananas purchased and the total cost of bananas.

Liula [17]

Answer:

Choice A, C and E

Step-by-step explanation:

Your table is poorly presented

Given

x y

$\begin{array}{cc} {3} & {1.47} \ \\ {5} & {2.45} \ \\ {9} & {4.41} \ \ \end{array}$

First, we calculate the constant of proportionality (k)

$k = \frac{y}{x}$

For (3,1.47)

$k = \frac{1.47}{3}$

$k = 0.49$

For (5,2.45)

$k = \frac{2.45}{5}$

$k = 0.49$

For (9,4.41)

$k = \frac{4.41}{9}$

$k = 0.49$

From the above calculations, the constant of proportionality is 0.49.

So, the usable rows must also have 0.49 as their constant of proportionality

Choice A

$(x,y) = (2,0.98)$

$k = \frac{0.98}{2}$

$k = 0.49$ --- This is usable

Choice B

$(x,y) = (7,4.45)$

$k = \frac{4.45}{7}$

$k = 0.64$ --- This is not usable

Choice C

$(x,y) = (6,2.94)$

$k = \frac{2.94}{6}$

$k = 0.49$ --- This is usable

Choice D

$(x,y) = (1,0.54)$

$k = \frac{0.54}{1}$

$k = 0.54$ ---- This is not usable

Choice E

$(x,y) = (8,3.92)$

$k = \frac{3.92}{8}$

$k = 0.49$ --- This is usable

5 0

3 years ago