All categories

4 years ago

What would the coordinates of the new image be? (View Picture)

Mathematics

1 answer:

tino4ka555 [31]4 years ago

7 0

Answer:

T(1, 5), R(7, 7), A(7, 1), M(4, 5)

Step-by-step explanation:

The mapping for -90° rotation is (x, y) ⇒ (y, -x).

for example, T(-5, 1) ⇒ T'(1, 5)

If you're doing this with pencil and paper, you can draw the image and axes the way it is, then rotate your drawing 90° clockwise (so the axes line up) and copy it into the first quadrant.

You might be interested in

Which of the following is not true?<br> O √16 +4√4+5<br> О 3п > 9<br> O √27+3 ><br> O 5-√24 1

GalinKa [24]

Answer:

Hello there! I believe b or d

6 0

3 years ago

Select the correct answer.

SCORPION-xisa [38]

Answer:

d. 18

Step-by-step explanation:

g(x)=3x-3

3(7)-3

21-3

=18

7 0

3 years ago

Can someone plz help how to solve this by showing the work to

harkovskaia [24]

Just multiply the number out of the parentheses with the ones inside. So -8 times 9=-72 and 3q times -8=-24q. Now keep the same operation, which is subtraction in this case.So, -72--24q or -72+24q will be the correct answer.

7 0

3 years ago

IM SO CONFUSED! SOMEONE HELP

MariettaO [177]

Answer:

Uhh.. Where does it first start at?

Step-by-step explanation:

3 0

3 years ago

What is the solution for x in the given equation? The square root of 9x +7 + the square root of 2x = 7

cestrela7 [59]

Answer:

The solution is x =2 for the given equation $\sqrt{9x+7} +\sqrt{2x}=7$

Step-by-step explanation:

We need to find the solution for x in the given equation.

$\sqrt{9x+7} +\sqrt{2x}=7$

Solving:

Subtract $\sqrt{2x}$ from both sides

$\sqrt{9x+7} =7-\sqrt{2x}$

Taking square on both sides

$(\sqrt{9x+7})^2 =(7-\sqrt{2x})^2\\Using\,\, (a-b)^2 = a^2-2ab-b^2\\9x+7=(7)^2-2(7)(\sqrt{2x})+(\sqrt{2x})^2\\9x+7=49-14\sqrt{2x}+2x\\9x-2x+7-49=-14\sqrt{2x}\\7x-42=-14\sqrt{2x}\\Taking\,\,square\,\,on\,\,both\,\,sides\\(7x-42)^2=(-14\sqrt{2x})^2\\49x^2-2(7x)(42)+(42)^2= 196(2x)\\49x^2-588x+1764=392x\\49x^2-588x+1764-392x=0\\49x^2-980x+1764=0\\Using \,\,quadratic \,\, equation \,\,to \,\, find \,\, value \,\, of \,\, x \\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\a= 49, \, b= -980 \,\,and\,\, c = 1764$