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tatiyna
3 years ago
11

Acetylene gas is often used in welding torches because of the very high heat produced when it reacts with oxygen gas, producing

carbon dioxide gas and water vapor. Calculate the moles of acetylene needed to produce of carbon dioxide. Be sure your answer has a unit symbol, if necessary, and round it to significant digits.
Chemistry
1 answer:
serg [7]3 years ago
5 0

Answer:

2.25 moles ≈ 2.3 moles

Explanation:

Full Question:

Acetylene C2H2 gas is often used in welding torches because of the very high heat produced when it reacts with oxygen O2 gas, producing carbon dioxide gas and water vapor. Calculate the moles of oxygen needed to produce 1.5mol of water. Be sure your answer has a unit symbol, if necessary, and round it to significant digits.

First off, let's put the equation of the reaction sown;

C2H2 + O2 → H2O + CO2

Upon balancing, we have;

2C2H2 + 3O2 → 2H2O + 4CO2

So from the equation;

3 mole of oxygen is required in order to produce 2 mole of water vapour.

The question asks to calculate moles of oxygen needed to produce 1.5mol of water

This leads us to;

3 moles = 2 moles

x moles = 1.5 moles

x = ( 1.5 * 3 ) / 2

x = 4.5 / 2 = 2.25 moles ≈ 2.3 moles

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Can someone tell me how to solve this step by step? I got the answer but I want to know how to solve it I have a test !!!!
UNO [17]
C becuase that is the one that you would have to do becuase that is the only option
6 0
3 years ago
20 poll
aleksley [76]

Answer: n=15.56moles

Explanation:

PV = nRT

where  

P is pressure in atmospheres

V is volume in Liters

n is the number of moles of the gas

R is the ideal gas constant = given as (0.0821L -atm/k-mol

PV = nRT

n= PV/RT

n= (1.5 X 230)/ (0.0821  X 270)

n= 15.56 moles

5 0
3 years ago
Ethanol has a density of 0.789 g/cm3. What is the mass of 423 cm3 of ethanol? M = (D)(V)
Ivahew [28]

Answer:

<h2>The answer is 334 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of ethanol = 423 cm³

density = 0.789 g/cm³

So we have

mass = 0.789 × 423 = 333.747

We have the final answer as

<h3>334 g</h3>

Hope this helps you

6 0
3 years ago
8. As the temperature of a mixture increases, one part of the mixture may 2 points
disa [49]

Answer:

It's false

Explanation:

Mixtures are always combinations of the same compounds that are at different states.

8 0
3 years ago
How many milligrams are in 2.5 kg?
ludmilkaskok [199]

Answer:

There are 2500000 milligrams in 2.5 kg

7 0
3 years ago
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