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Ludmilka [50]
2 years ago
11

Competition increases as _____.

Chemistry
1 answer:
ad-work [718]2 years ago
3 0
Population density increases
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Suppose that you are performing a titration on a monoprotic acid. Titration of this monoprotic acid required a volume of 0.1L of
Alex73 [517]

Answer: A) More base is likely required to reach the endpoint for the diprotic acid than for the monoprotic acid under these conditions

Explanation:

The monoprotic acid (HA) has a valency of 1 and diprotic acid  (H_2A) has a valency of 2.

As the concentration and volume of the diprotic acid and the monoprotic acids are equal.

The neutralization reaction for monoprotic acid is:

HA+BOH\rightarrow BA+H_2O

The neutralization reaction for diprotic acid is:

H_2A+2BOH\rightarrow B_2A+2H_2O

Thus more number of moles of base are required for neutralization of diprotic acid and thus the volume required will be more as concentration and volume of the diprotic acid and the monoprotic acids are equal.

6 0
3 years ago
A boy who weighs 30 kg is skateboarding at a speed of 5 m/s. What is the boys kinetic energy?
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I’m pretty sure it’s 150 joules
5 0
3 years ago
The cis and trans geometric isomers of a compound have different chemical and physical properties. Draw the structure of the geo
frutty [35]

<u>Answer:</u> The structure of the geometrical isomers are attached below.

<u>Explanation:</u>

Cis- and Trans- isomers are the geometrical isomers which have same chemical formula but different structural formula

According to CIP rule, the groups on the doubly bonded carbon atoms are given priorities based on the the atomic masses of first connected atom.

If the highest priority groups are on the same side, it is known as cis-form and if the highest priority groups are on opposite side, it is known as trans-form.

We are given a chemical compound, which is 2-pentene.

In this the highest priority groups are methyl and ethyl groups.

When the groups are on the same side, it forms cis-form and when the groups are on the opposite side, it forms trans-form

The structure of the geometrical isomers are attached below.

7 0
2 years ago
I need help with number 5 part b please!
Afina-wow [57]
Answer is 3Mg + N2 —--> Mg3 N2
6 0
3 years ago
A sample of gas X occupies 10 mº at a pressure of 120 kPa.
Mashutka [201]

Answer:

The new pressure of the gas comes out to be 400 KPa.

Explanation:

Initial volume of gas = V = 10\textrm{ m}^{3}

Initial pressure of gas = P = 120 KPa

Final volume of gas = V' = 3\textrm{ m}^{3}

Assuming temperature to be kept constant.

Assuming final pressure of the gas to be P' KPa

PV = P'V' \\120\textrm{ KPa}\times 10\textrm{ m}^{3} = \textrm{P'}\times 3\textrm{ m}^{3} \\\textrm{P'} = 400\textrm{ KPa}

New pressure of gas = 400 KPa

5 0
2 years ago
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