D.
The products will have at least 2 Na atoms and 1 O atom.
<h3>Further explanation</h3>
If we refer to the law of mass conservation, which states that
<em>In a closed system, the masses before and after the reaction are the same
</em>
then the number of atoms in the reactance will be the same as the number of atoms in the product
In this problem it is known that Na₂O is one of the reactants so that the product of Na atoms and O atoms will at least equal the number of atoms in the bond, namely 2 Na and 1 O
Like an example of this Na₂O reaction:
Na₂O + H₂O ⇒ 2 NaOH
Na : left =2, right = 2
O : left=2, right = 2
Answer:
denotes the molar hydrogen ion concentration
Explanation:
The answer is 4.69 x 10⁻¹⁹ I hope this helped!
Wouldn’t it be half of each? For 36 I guess is 18 and 54 will be 27, (NOT SURE)
Thank you for posting your question here. Below is the solution:
HNO3 --> H+ + NO3-
<span>HNO3 = strong acid so 100% dissociation </span>
<span>** one doesn't need to find the molarity of water since it is the solvent </span>
<span>0M HNO3 </span>
<span>1x10^-6M H3O+ </span>
<span>1x10^-6M NO3- </span>
<span>1x10^-8M OH-.....the Kw = 1x10^-14 = [H+][OH-] </span>
<span>you have 1x10^-6M H+ so, 1x10^-14 / 1x10^-6 = 1x10^-8M OH- </span>
<span>1x10^-6 Ba(OH)2 = strong base, 100% dissociation </span>
<span>1x10^-6M Ba2+ </span>
<span>2x10^-6M OH- since there are 2 OH- / 1 Ba2+ </span>
<span>0M Ba(OH)2 </span>
<span>5x10^-9M H3O+</span>
