Answer:don’t mind this I just needed to answer five questions and im not smart
Explanation:
Oh yeah I just got cheated lol lol lol lol
Answer:
W_net = μ 5.58, μ = 0.1 W_net = 0.558 J
Explanation:
The work is defined by the related
W = F. d = F d cos θ
where bold indicates vectors.
In the case, the work of the friction force on a circular surface is requested.
The expression for the friction force is
fr = μ N
the friction force opposes the movement, therefore the angle is 180º and the cos 180 = -1
W = - fr d
the path traveled half the length of the circle
L = 2 π R
d = L / 2
d = π R
we substitute
W = - μ N d
Total work is initial to
W_neto = - μ π R (N_b - N_a)
let's calculate
W_net = - μ π 0.550 (0.670 - 3.90)
W_net = μ 5.58
for the complete calculation it is necessary to know the friction coefficient, if we assume that μ = 0.1
W_net = 0.1 5.58
W_net = 0.558 J
Answer:
Explanation:
The speed of the astronaut can be found with the help of law of conservation of momentum .
mv = MV , M is mass of astronaut , m is mass of object thrown , v is velocity of object thrown and V is velocity of astronaut.
Putting the values
77.5 x V = .94 x 12
V = .14554 m /s
This will be the uniform velocity of astronaut.
Distance to be covered = 37.3 m
time taken = distance / velocity
= 37.3 / .14554
= 256.28 s
= 4.27 minutes.
Answer:
Explanation:
This question is based on the Law of Conservation of Angular Momentum.
Angular momentum (L) equals the moment of inertia (I) times the angular speed (ω).
L = Iω
If momentum is conserved,
I₁ω₁ = I₂ω₂
Data:
I₁ = 3.5 kg·m²s⁻¹
ω₁ = 6.0 rev·s⁻¹
I₂ = 0.70 kg·m²s⁻¹
Calculation:
