Answer:
the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms
Explanation:
Given the data in the question;
first we determine the rotational latency
Rotational latency = 60/(3600×2) = 0.008333 s = 8.33 ms
To get the longest time, lets assume the sector will be found at the last track.
hence we will access all the track, meaning that 127 transitions will be done;
so the track changing time = 127 × 15 = 1905 ms
also, we will look for the sectors, for every track rotations that will be done;
128 × 8.33 = 1066.24 ms
∴The Total Time = 1066.24 ms + 1905 ms
Total Time = 2971.24 ms
Therefore, the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms
Conductors allow<span> for </span>charge<span> transfer </span>through<span> the free movement of </span><span>electrons
</span>
Answer:
In Motion in Two and Three Dimensions, we examined the basic concepts of circular motion. An object undergoing circular motion, like one of the race cars shown at the beginning of this chapter, must be accelerating because it is changing the direction of its velocity. We proved that this centrally directed acceleration, called centripetal acceleration, is given by the formula
\[{a}_{\text{c}}=\frac{{v}^{2}}{r}\]
Answer:
1.865 * 10^-4 L
Explanation:
The equation of the reaction is:
4OH^-(aq) ----->2H2O(l) + O2(g) + 4e
Since one mole of oxygen which occupies 22.4 L is produced in the electrolysis of water by 4 Faraday of electricity as shown in the equation above;
Then;
4 * 96500 C liberates 22.4 L of oxygen
60 * 60 * 0.0200 C will liberate 60 * 60 * 0.0200 * 22.4/4 * 96500
= 1.865 * 10^-4 L
Newton's law of universal gravitation states that every particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
