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irga5000 [103]
3 years ago
13

What is the processes called when matter, that is a liquid, transforms into a solid?

Physics
1 answer:
AURORKA [14]3 years ago
4 0
Oh yeah I just got cheated lol lol lol lol
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A physical pendulum consists of a vertical board of of mass 6.12 kg, length 191 cm, and width 12 cm hanging from a horizontal, f
LiRa [457]

Answer

A. 229.192m/s

B 158.6m/s

Explanation:

See attached file

8 0
4 years ago
13. For an object to appear transparent, what interaction must occur between light waves and the object they hit?
Svetlanka [38]

Answer:

The answer is B

Explanation:

The absorption happens when photons from light hit atoms and molecules, and they vibrate because of that specific interaction. Then the heat ejects from the object in the format of thermal energy.

6 0
3 years ago
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How far does a car travel if is going 4.0 m/s and accelerates to 3.5m/s2 for 5s ?
qwelly [4]

Answer:

15 or 20 miles

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7 0
4 years ago
A reaction taking place in a container with a piston-cylinder assembly absorbs 4850. J of heat and has a change in the internal
Maslowich

Answer:

V_f = 16.3 Ltr

Explanation:

As per first law of thermodynamics we know that

heat absorbed = change in internal energy + Work done

so we have

Heat = 4850 J

\Delta U = 1618.5 J

so work done is given as

4850 = 1618.5 + W

W = 3231.5 J

now we know that at constant pressure the work done is given as

W = P\Delta V

3231.5 = P(V_f - V_i)

3231.5 = 5.5 \times 1.01 \times 10^5(V_f - 10.5 \times 10^{-3})

V_f = 16.3 \times 10^{-3} m^3

or we have

V_f = 16.3 Ltr

6 0
3 years ago
How do I calculate equilibrant and fx and fy. I don't understand what they are asking
Natasha2012 [34]

(a) The equilibrant C for force of vector A and B is 3.43 N.

(b) The equilibrant C for fx of vector A and B is 2.1 N.

(c) The equilibrant  C, for fy of vector A and B is 2.12 N.

<h3>What is equilibrant force?</h3>

An equilibrant force is a single force that will bring other bodies into equilibrium.

<h3>From configuration 1:</h3>

Vector A: mass = 0.2 kg, θ = 20⁰

Vector B: mass = 0.15 kg, θ = 80⁰

Fx = mg cosθ

Fy = mg sinθ

where;

  • m is mass
  • g is acceleration due to gravity

<h3>Vector A</h3>

Force of A due to its weight

F(A) = mg

F(A) = 0.2 x 9.8 = 1.96 N

Fx = (0.2 x 9.8) cos(20) = 1.84 N

Fy = (0.2 x 9.8) sin(20) = 0.67 N

<h3>Resultant force</h3>

R = √(0.67² + 1.84²)

R = 1.96 N

<h3>Vector B</h3>

Force of B due to its weight

F(B) = mg

F(B) = 0.15 x 9.8

F(B) = 1.47 N

Fx = (0.15 x 9.8) cos(80) = 0.26 N

Fy = (0.15 x 9.8) sin(80) = 1.45 N

<h3>Resultant force </h3>

R = √(0.26² + 1.45²)

R= 1.47 N

<h3>Equilibrant  C of vector A and B</h3>

Equilibrant force:

Force, C = 1.96 N + 1.47 N

Force, C = 3.43 N

Equilibrant FX:

Fx, C = Fx(A) + Fx(B)

Fx, C = 1.84 N + 0.26 N = 2.1 N

Equilibrant FY:

Fy, C = Fy(A) + Fy(B)

Fy, C =0.67 N + 1.45 N = 2.12 N

Learn more about equilibrant force here: brainly.com/question/8045102

#SPJ1

3 0
2 years ago
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