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Rzqust [24]
3 years ago
8

Objects 1 and 2 attract each other with a electrostatic force of 72.0 units. If the charge of object 1 is doubled AND the charge

of object 2 is tripled, then the new electrostatic force will be ____ units
Physics
1 answer:
lbvjy [14]3 years ago
5 0

Answer:

432 units

Explanation:

Let the charges be q and Q separated by a distance r. The electrostatic force , F = kqQ/r² = 72 units. If q = 2q and Q = 3Q, then the new electrostatic force is

F = k × 2q × 3Q/r² = 6kqQ/r² = 6 × 72 = 432 units

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If you are pushing on a box with a force of 20 N and there is a force of 7 N on the box due to sliding friction, what is the net
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I think you would do 20+7 = 27N as the net force
7 0
3 years ago
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Need some help please
11Alexandr11 [23.1K]

Answer:

x^2\neq -\frac{5}{13}

First option

Explanation:

<u>Operations with functions </u>

Given two functions f, g, we can perform a number of operations with them including addition, subtraction, product, division, composition, and many others .

We have

f(x)=20x^3-7x^2+3x-7

g(x)=-13x^2-5

We are required to find

\displaystyle \frac{f}{g}(x)

We simply divide f by g as follows

\displaystyle \frac{f}{g}(x)=\frac{20x^3-7x^2+3x-7}{-13x^2-5}

We know rational functions may have problems if the denominator can be zero for some values of x. We must find out if there are such values and exclude them from the domain of the new-found function. We must ensure

-13x^2-5\neq 0

or equivalently

x^2\neq -\frac{5}{13}

Thus the first option is correct

Note: Since x^2 is always a positive number (for x real), our function does not really have any restriction in its domain

8 0
3 years ago
A spaceship has a momentum of 45,000 kg-m/s to the right, and a mass of 200 kg. What is the magnitude of its velocity?
amm1812

Answer:

v = 225 m/s

Explanation:

Given,

The momentum of the spaceship, p = mv    = 45,000 Kg m/s

The mass of the spaceship, m = 200 Kg

The velocity of the spaceship, v = ?

The relationship between the momentum, mass, and velocity is given by the formula

                                    p = mv     Kg m/s

Therefore,

                                    v = p/m     m/s

Substituting the values in the above equation

                                     v = 45,000 Kg m/s   /  200 Kg

                                        = 225 m/s

Hence, the magnitude of velocity of the spaceship is, v = 225 m/s

5 0
3 years ago
Read 2 more answers
One ounce of a well-known breakfast cereal contains 103 Calories (1 food Calorie = 4186 J). If 1.6% of this energy could be conv
faust18 [17]

Answer:

the heaviest barbell that could be lifted  is 390.6kg

Explanation:

Hello!

To solve this question you must follow the following steps

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5 0
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Answer:

elements are the same columns are similar in there property

Explanation:

3 0
2 years ago
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