Question

As a dilligent physics student, you carry out physics experiments at every opportunity. At this opportunity, you carry a 1.39-m-long rod as you jog at 3.37 m/s, holding the rod perpendicular to your direction of motion. What is the strength of the magnetic field that is perpendicular to both the rod and your direction of motion and that induces an EMF of 0.291 mV across the rod

Answer 1

Answer:

The strength of magnetic field is $6.21 \times 10^{-5}$ T

Explanation:

Given:

Length of rod $l = 1.39$ m

Velocity $v = 3.37$ $\frac{m}{s}$

Induced emf $= 0.291 \times 10^{-3}$ V

According to the faraday's law

Induced emf = $Blv$

We have to find strength of the magnetic field,

   $B = \frac{0.291 \times 10^{-3} }{1.39 \times3.37}$

   $B = 6.21 \times 10^{-5}$ T

Therefore, the strength of magnetic field is $6.21 \times 10^{-5}$ T