Answer:
a) a = 4.9 m / s², N = 16.97 N and b) F = 9.8 N
Explanation:
a) For this exercise we will use Newton's second law, we write a reference system with the x axis parallel to the plane, see attached, in this system the only force we have to break down is weight, let's use trigonometry
sin 30 = Wx / W
cos 30 = Wy / W
Wx = W sin30
Wy = W cos 30
Let's write the equations on each axis
X axis
Wx = ma
Y Axis
N- Wy = 0
N = Wy = mg cos 30
N = 2.0 9.8 cos 30
N = 16.97 N
We calculate the acceleration
a = Wx / m
a = mg sin 30 / m
a = g sin 30
a =9.8 sin 30
a = 4.9 m / s²
b) For the block to move with constant speed, the acceleration must be zero, so the force applied must be equal to the weight component
F -Wx = 0
F = Wx
F = m g sin 30
F = 2.0 9.8 sin 30
F = 9.8 N
Answer:It’s 5 I believe
Explanation: it says to round to the nearest thousandths, so it’ll be 5.
Answer:
The maximum height the pebble reaches is approximately;
A. 6.4 m
Explanation:
The question is with regards to projectile motion of an object
The given parameters are;
The initial velocity of the pebble, u = 19 m/s
The angle the projectile path of the pebble makes with the horizontal, θ = 36°
The maximum height of a projectile,
, is given by the following equation;

Therefore, substituting the known values for the pebble, we have;

Therefore, the maximum height of the pebble projectile,
≈ 6.4 m.
Answer: The work done in J is 324
Explanation:
To calculate the amount of work done for an isothermal process is given by the equation:

W = amount of work done = ?
P = pressure = 732 torr = 0.96 atm (760torr =1atm)
= initial volume = 5.68 L
= final volume = 2.35 L
Putting values in above equation, we get:

To convert this into joules, we use the conversion factor:

So, 
The positive sign indicates the work is done on the system
Hence, the work done for the given process is 324 J
<h3>
Answer:</h3>
30.4 km/hr
<h3>
Explanation:</h3>
<u>We are given</u>;
- Speed in the first 2 hours as 25 km/hr
- Speed in the next 3 hours as 34 km/hr
We are required to determine the average velocity in km/hr
- To get the average velocity we divide total distance by total time.
- Thus, we need to determine the total distance
Distance = Speed × time
Distance covered in the first 2 hours;
= 25 km/hr × 2 hours
= 50 km
Distance in the next 3 hours
= 34 km/hr × 3 hours
= 102 km
Therefore, total distance = 50 km + 102 km
= 152 km
Total time = 2 hrs + 3 hrs
= 5 hours
Therefore;
Average speed = 152 km ÷ 5 hours
= 30.4 km/hr
Thus, the average speed is 30.4 km/hr