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umka21 [38]
3 years ago
9

A 0.0100-kilogram grape hangs from a vine 1.50 meters from the ground. What is the potential energy of the grape?

Physics
2 answers:
ludmilkaskok [199]3 years ago
8 0
The potential energy is defined as Ep=m*g*h where m is the mass of the body, g=9.81 m/s² and h is the height of the body. In our case m=0.01 kg and h=1.5 m. So when we input the values into the equation:

Ep=0.01*9.81*1.5= 0.14715 J. 

So the potential energy of a grape is Ep=0.14715 J. 
FromTheMoon [43]3 years ago
3 0

Answer:

0.147

Explanation:

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R is proportional to the length of the wire:

R ∝ length

R is also proportional to the inverse square of the diameter:

R ∝ 1/diameter²

The resistance of a wire 2700ft long with a diameter of 0.26in is 9850Ω. Now let's change the shape of the wire, adding and subtracting material as we go along, such that the wire is now 2800ft and has a diameter of 0.1in.

Calculate the scale factor due to the changed length:

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Scale factor due to changed diameter:

k₂ = 1/(0.1/0.26)² = 6.76

Multiply the original resistance by these factors to get the new resistance:

R = R₀k₁k₂

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R = 9850(1.037)(6.76)

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3 years ago
A 0.11 N m torque is applied to a fan that was initially at rest. The fan has moment of inertia of 0.034 kg m2. Determine the ki
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2.72*10-3 Joules

Explanation:

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the angular velocity is

\omega = \alpha/t\\\\\omega =3.23/8\\\\\omega =0.4 rad/s

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e = Emissivity = 1

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Using Stefan's law, Power output of the sun is given as

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