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sleet_krkn [62]
2 years ago
13

The weight of an object on the surface of mass is 1850 Newton and its mass is 500kg.Find the acceleration due to gravity on mars

​
Physics
1 answer:
Fudgin [204]2 years ago
3 0

F = m.a

a = F/m

a = 1850/500

a = 3.7 m/s²

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Before CDs and cassette tapes, there were vinyl records. The most comon spun with an angular velocity of 33.3revolutionsperminut
sashaice [31]

Answer:

539.5°

Explanation:

33.3 revolutions per minute

1 revolution = 360°

1 minute = 60 seconds

hence

33.3 revs ----> 1 minute = 60 seconds

X revs -----------> 2.70 seconds

X = (33.3 x 2.7)÷60 = 1.4985 revolutions in 2.70 seconds

1.4985 revolutions = 1.4985 x 360 = 539.46

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3 years ago
Boiling point (when a liquid change to gas) is a physical property of matter. I want to determine if the amount of water will ha
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E

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4 0
3 years ago
A 60 mAs results in an exposure of 85 mGya, with all factors remaining the same, what would the new exposure be if 120 mAs is us
Cloud [144]

Answer: d₂ = 170 mGya

Explanation:

the relationship between absonbed 'd' and exposure 'E' is given as;

D(Gv) = F . x (AS/xB)

F is a conversion coefficient depending on medium

so we can simply write

d₁/d₂ = x₁/x₂

Given that;

our x₁ = 60 mAs, x₂ = 120 mAs,  d₁ = 85 mGya, d₂ = ?

from the given formula,

d₂ = (x₂d₁ / x₁)

now we substitute

d₂ = (120 × 85) / 60

d₂ = 170 mGya

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8 0
3 years ago
You are going sledding with your little cousins during a well-earned break. You push your 23 kg cousin so that they have a speed
pogonyaev

Answer:

kinetic energy = 414 J

Explanation:

given data

mass = 23 kg  

speed = 6 m/s  

height = 17 m    

to find out

kinetic energy

solution

we get kinetic energy that is express as

kinetic energy = 0.5 × m × v²    ..........................1

here m is mass and v is speed so

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kinetic energy = 0.5 × 23 × 6²

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7 0
3 years ago
Read 2 more answers
From the top of a cliff overlooking a lake, a person throws two stones. The two stones have identical initial speeds of v0 = 13.
Alina [70]

Answer:

X = 15.88 m

Explanation:

Given:

Initial Velocity V₀ = 13.4 m/s

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g = 9.8 m/s²

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so from motion 2nd equation at Height h = 0

h = V₀y t + 1/2 (-g) t ²                                (ay = -g)

0 = 13.4 sin 30.1° t - 0.5 x 9.81 x t²           (V₀y = V₀ Sin θ)

⇒  t = 1.37 s

Now For Horizontal distance  X, ax =0m/s²

X = V₀x t + 1/2 (ax) t ²

X = 13.4 m × cos 30.1° x 1.37 s + 0

X = 15.88 m

8 0
3 years ago
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