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lara31 [8.8K]
3 years ago
13

What element has 3 electrons in the 2p sublevel?

Chemistry
2 answers:
Serjik [45]3 years ago
6 0
The element should be nitrogen
Lunna [17]3 years ago
6 0
Aufbau says that the sublevels fill 1s2, 2s2, 2p6. That would mean that you must have filled 1 and 2 s (=4) and 3 more.

Last I checked, 3 + 4 = 7. Which element has 7 electrons?

I'll give you a hint: its atomic number is 7. Another hint: its symbol is N.
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If I use the dropper to add 10 mL of drink mix to 50 mL of water, what is the
Yuliya22 [10]

Answer:

16.7%

Explanation:

From the question given above, the following data were obtained:

Volume of drink mix = 10 mL

Volume of water = 50 mL

Percentage of drink mix =?

Next, we shall determine the total volume of the solution. This can be obtained as follow:

Volume of drink mix = 10 mL

Volume of water = 50 mL

Total volume of solution =?

Total volume of solution = (Volume of drink mix) + (Volume of water)

Total volume of solution = 10 + 50

Total volume of solution = 60 mL

Finally, we shall determine the percentage of the drink mix in the solution. This can be obtained as follow:

Volume of drink mix = 10 mL

Total volume of solution = 60 mL

Percentage of drink mix =?

Percentage of drink mix = Vol. of drink mix / total volume × 100

Percentage of drink mix = 10/60 × 100

Percentage of drink mix = 16.7%

4 0
3 years ago
Draw a structural formula of an alkene or alkenes (if more than one) that undergo acid-catalyzed hydration and without rearrange
lara31 [8.8K]

Answer:

-) 2-methylbut-2-ene

-) 2-methylbut-1-ene

-) 3-methylbut-1-ene

Explanation:

in this case, the hydration of alkenes is a <u>marknovnikov reaction</u>, this means that the "OH" group would be added in the <u>most substituted carbon</u> of the double bond. (Figure 1)

For 2-methylbut-2-ene the most substituted carbon is the <u>tertiary carbon</u> (the carbon in the right of the double bond), so we will obtain the desired molecule. In 2-methylbut-1-ene the most substituted carbon is again the <u>tertiary carbon</u> (the carbon in the bottom of the double bond), so we will obtain 2-methyl-2-butanol. Finally, for 3-methylbut-1-ene the carbocation would be formed on carbon 3, this is a secondary carbocation. We can obtain a most stable carbocation if we do a <u>hydride shift</u> (Figure 2). With this new molecule is possible to obtain 3-methylbut-1-ene.

6 0
4 years ago
If a certain person has a mass of 250kg on earth, would that person's mass be on the moon, if the moon's gravity is 1.62m/s2? *
xxMikexx [17]

Answer:

it remains the same

Explanation:

mass is like name is not changed any where mass express the amount of matter in an object which is fixed any where regardless its gravity

7 0
3 years ago
To measure the amount of iron in a certain type of iron ore, an analytical chemist dissolves a sample in strong acid and titrate
Fiesta28 [93]

Answer:

\% Fe=11.4\%

Explanation:

Hello!

In this case, for the described chemical reaction, we find it is:

8H^+(aq)+5Fe^{2+}(aq)+MnO_4^-(aq)\rightarrow 5Fe^{3+}(aq)+Mn^{2+}(aq)+4H_2O(l)

Because it says that the iron is dissolved in a strong acid which provides addition hydrogen ions to the reaction media. Thus, for the questions attached on the figure we find:

- This a REDOX reaction because we see iron is being oxidized from 2+ to 3+ and manganese reduced from +7 to +2.

- Since it is a redox reaction and the oxidized species is that undergoing an oxidation number increase, we evidence iron goes from +2 to +3, which means iron is the oxidized species.

- In this case, for the used 59.2 mL (0.0592 L) of the 0.2000 M solution of potassium permanganate, we can compute the consumed grams of iron via stoichiometry including the 5:1 mole ratio between them in the chemical reaction:

m_{Fe^{2+}}=0.0592L*0.2000\frac{molMnO_4^-}{L}*\frac{5molFe^{2+}}{1molMnO_4^-}  *\frac{55.85gFe^{2+}}{1molFe^{2+}} \\\\m_{Fe^{2+}}=3.31gFe^{2+}

It means that the percent of iron in that sample is:

\% Fe=\frac{3.31g}{29.00g} *100\%\\\\\% Fe=11.4\%

Best regards.

5 0
3 years ago
A 54.2 L sample of gas at 115 K is heated to 345 K, at constant pressure. What volume does the gas now occupy?
sweet [91]
V1/T1 = V2/T2, so 
<span>V2 = V1 * T2 / T1 </span>
<span>V2 = 54.2 L * 345 K / 115 K </span>
<span>V2 = 163 L</span>
7 0
4 years ago
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