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Oxana [17]
3 years ago
10

you record the sea temperature at 12 degrees North 45 degrees West to be 27.5 degrees Celcius the humidity to be very high and a

very light breeze,do you expect a hurricane to form in these conditions?Explain why or why not
Chemistry
1 answer:
Cerrena [4.2K]3 years ago
4 0
 For a hurricane to form, the sea temperature must be at least 26.7. The temperature of the water in the problem is 27.5. 
Another condition is that there should be little wind in the area. The problem states that there is a very light breeze. Finally, the humidity must be high.
Therefore, it is expected that a hurricane will form at the given location.
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<span>Hope this answers your question!</span>
4 0
3 years ago
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3 0
3 years ago
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You can purchase nitric acid in a concentrated form that is 70.3% HNO3 by mass and has a density of 1.41 g/mL. Describe exactly
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6 0
3 years ago
Read 2 more answers
Pure carbon dioxide (PCO2 = 1 atm) decomposes at high temperature. For the reaction system 2 〖CO〗_2 (g) ⇌2 CO(g)+ O_2 (g) Is thi
julia-pushkina [17]

Answer:

The reaction decomposes more as T increases, therefore it is ENDOTHERMIC, meaning it requires energy to form CO and O₂.

Kp for each specie...

Kp = CO^2 O2 / (CO2)^2

for

T = 1500

Assume 1 atm for CO2, after % dissociation

P-CO2 left = 1*(1-0.048/100)= 0.99952

P-CO formed = 1-0.99952 = 0.00048

P-O2 = (1-0.99952)/2 = 0.00024

so..

Kp = CO^2 O2 / (CO2)^2

Kp = (0.00048^2)(0.00024) / (0.99952^2) = 5.53*10^-11

T = 2500

Assume 1 atm for CO2, after % dissociation

P-CO2 left = 1*(1-17.6/100)= 0.824

P-CO formed = 1-0.824= 0.176

P-O2 = (1-0.176)/2 = 0.088

so..

Kp = CO^2 O2 / (CO2)^2

Kp = (0.176^2)(0.088) / (0.824^2) =0.0040

T = 3000

Assume 1 atm for CO2, after % dissociation

P-CO2 left = 1*(1-54.8/100)= 0.452

P-CO formed = 1-0.452= 0.548

P-O2 = (1-0.452)/2 = 0.274

so..

Kp = CO^2 O2 / (CO2)^2

Kp = (0.548^2)(0.274) / (0.452^2) =0.4027

Explanation:

6 0
3 years ago
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