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3 years ago

A) Select the strongest acid:H2Te, GeH4, AsH3, H2S, SiH3

Chemistry

1 answer:

sineoko [7]3 years ago

4 0

Answer:

(A). H2S.

(B). BrO-.

(C). H2SbO3 .

(D). HClO4.

(E). CH3NH2.

(F). HClO > HBrO > HIO.

Explanation:

(A). The strongest acid is H2S because it has the lowest atomic size. If we move from the left side of the periodic table to the right side of the periodic table the atomic size decreases. As the atomic size decreases, it will be easier for H^+ ion to be released. Therefore, the ease of releasing Hydrogen ion makes H2S more acidic than the others in this group.

(B). BrO- is more basic because of bond pair - lone pair repulsion. BrO2- , BrO4-, and ClO2- exhibit resonance and therefore, they do not possess good basic features.

(C). H2SbO3 has the lowest pKa because the atomic size of Sb is greater than As and P , As is greater than P. This means that It is more difficult to remove Hydrogen ion from Sb.

(D). HClO4 is the Acid with the highest pKa because of high resonance.

(E). CH3NH2 is more basic because it has the highest electron Density. In BrNH2, the bromine ion reduces the electron Density.

(F). In halogens, as one goes down the group in the periodic table the acidic properties decreases, hence, HClO > HBrO > HIO.

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3 years ago

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In which system does a spontaneous redox reaction produce electrical energy?

Vladimir [108]

Had to look for the options and here is my answer.
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2 years ago

7.66 Write balanced equations for the following reactions: (a) potassium oxide with water, (b) diphosphorus trioxide with water,

White raven [17]

Explanation:

(a) potassium oxide with water

$K_2O(s)+H_2O(l)\rightarrow 2KOH(aq)$

According to reaction,1 mole of potassium oxide reacts with 1 mole of water to give 1 mole of potassium hydroxide.

(b) diphosphorus trioxide with water

$P_2O_3(s)+3H_2O(l)\rightarrow 2H_3PO_3(aq)$

According to reaction,1 mole of diphosphorus trioxide reacts with 2 moles of water to give 2 moles of phosphorus acid.

(c) chromium(III) oxide with dilute hydrochloric acid,

$Cr_2O_3(s)+6HCl(aq)\rightarrow 2CrCl_3(aq)+3H_2O(l)$

According to reaction,1 mole of chromium(III) oxide reacts with 6 moles of hydrochloric acid to give 2 moles of chromium(III) chloride and 3 moles of water.

(d) selenium dioxide with aqueous potassium hydroxide

$SeO_2 (s)+2KOH (aq)\rightarrow K_2SeO_3(aq)+H_2O(l)$

According to reaction,1 mole of selenium dioxide reacts with 2 moles of potassium hydroxide to give 1 mole of potassium selenite and 1 mole of water.

6 0

3 years ago

Part A

Roman55 [17]

These are two questions and two answers

Question 1.

Answer:

7.33 × 10 ⁻³ c

Explanation:

1) Data:

a) m = 9.11 × 10⁻³¹ kg

b) λ = 3.31 × 10⁻¹⁰ m

c) c = 3.00 10⁸ m/s

d) s = ?

2) Formula:

The wavelength (λ), the speed (s), and the mass (m) of the particles are reltated by the Einstein-Planck's equation:

λ = h / (m.s)

h is Planck's constant: h= 6.626×10⁻³⁴J.s

3) Solution:

Solve for s:

s = h / (m.λ)

Substitute:

s = 6.626×10⁻³⁴J.s / ( 9.11 × 10⁻³¹ kg × 3.31 × 10⁻¹⁰ m) = 2.20 × 10 ⁶ m/s

To express the speed relative to the speed of light, divide by c = 3.00 10⁸ m/s

s = 2.20 × 10 ⁶ m/s / 3.00 10⁸ m/s = 7.33 × 10 ⁻³

Answer: s = 7.33 × 10 ⁻³ c

Question 2.

Answer:

2.06 × 10 ⁻³⁴ m.

Explanation:

1) Data:

a) m = 45.9 g (0.0459 kg)

b) s = 70.0 m/s

b) λ = ?

2) Formula:

Macroscopic matter follows the same Einstein-Planck's equation, but the wavelength is so small that cannot be detected:

λ = h / (m.s)

h is Planck's constant: h= 6.626×10⁻³⁴J.s

3) Solution:

λ = h / (m.s)

Substitute:

λ = 6.626×10⁻³⁴J.s / ( 0.0459 kg × 70.0 m/s) = 2.06 × 10 ⁻³⁴ m

As you see, that is tiny number and explains why the wave nature of the golf ball is undetectable.

Answer: 2.06 × 10 ⁻³⁴ m.

5 0

2 years ago