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3 years ago

Identify the cfc with the shortest atmospheric lifetime

Chemistry

1 answer:

goldenfox [79]3 years ago

5 0

CFC-11 is typically the CFC with the shortest atmospheric lifetime.

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Which of the following equations represents Photosynthesis? 16CO2 + 6H2O -----> C6H12O6 + 6O22C6H12O6 + 6O2 -----> CO2 + 6

lidiya [134]

Answer:

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

Explanation:

Photosynthesis is the chemical process carried out by plants for the conversion of inorganic matter (carbon dioxide and water) into organic matter (glucose) with the release of oxygen, using light (sun energy).

So the chemical process may be represented by:

Word equation:

carbon dioxide + water + sun energy → glucose + oxygen

Skeleton equation:

CO₂ + H₂O + sun energy → C₆H₁₂O₆ + O₂

Balanced chemical equation:

6CO₂ + 6H₂O + sun energy → C₆H₁₂O₆ + 6O₂

Supressing the energy to show only the chemical compounds:

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

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3 years ago

All of the following are reasons why equations or balanced EXCEPT

Anni [7]

Answer:

monkey

Explanation:

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2 years ago

Acids or bases can be tested by chemical_________

DedPeter [7]

Answer:

acids or bases can be tested

by chemical indicators

7 0

2 years ago

Read 2 more answers

Hydrogen chloride, HCl, is classified as an Arrhenius acid because it produces(1) H+ ions in aqueous solution(2) Cl– ions in aqu

frozen [14]

Answer is (1) Produces H+ in aqueous solution

8 0

3 years ago

(06.03 MC) A 50.0 mL sample of gas at 20.0 atm of pressure is compressed to 40.0 atm of pressure at constant temperature. What i

oee [108]

Answer:

New volume is 25.0 mL

Explanation:

Let's assume the gas sample behaves ideally.

According to combined gas law for an ideal gas-

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

where, $P_{1}$ and $P_{2}$ represent initial and final pressure respectively

$V_{1}$ and $V_{2}$ represent initial and final volume respectively

$T_{1}$ and $T_{2}$ represent initial and final temperature (in kelvin) respectively

Here, $T_{1}=T_{2}$ , $V_{1}=50.0mL$ , $P_{1}=20.0atm$ and $P_{2}=40.0atm$

So, $V_{2}=\frac{P_{1}V_{1}T_{2}}{P_{2}T_{1}}=\frac{(20.0atm)\times (50.0mL)}{40.0mL}=25.0mL$

So, the new volume is 25.0 mL

6 0

3 years ago