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3 years ago

Why doesn’t a broken wineglass spontaneously fix itself, from a thermodynamic point of view?

Chemistry

2 answers:

deff fn [24]3 years ago

7 0

Answer:

C.Fixing a wineglass requires a large decrease in entropy.

Explanation:

Decrease in entropy is a non spontaneous process.

Entropy is the measure of randomness or disorder. For a process to be spontaneous the disorder or the randomness should increase. In a spontaneous process entropy increase or becomes positive.

A broken wine glass has more disorder than an unbroken glass. So a broken wine glass does not spontaneously fix itself as that would lead to a decrease in entropy.

Anarel [89]3 years ago

4 0

C. Fixing a wineglass requires a large decrease in entropy.

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Fluorine gas reacts with aqueous iron (II) iodine to produce iron (II) fluoride and iodine liquid What is the balanced chemical

Andru [333]

Answer:

F₂ (g) + FeI₂ (aq) → FeF₂ (aq) + I₂ (l)

Explanation:

Our reactants are:

F₂ → Fluorine gas, a dyatomic molecule

FeI₂ → Iron (II) iodine

Our products are:

I₂ → Iodine

FeF₂ → Iron (II) fluoride

Then, the reaction is:

F₂ (g) + FeI₂ (aq) → FeF₂ (aq) + I₂ (l)

We see it is completely balanced.

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2 years ago

Why is carbon dioxide nonpolar?

vovikov84 [41]

CO2 is a linear molecule and the Oxygen (O) atoms on each end are symmetrical. Polarity results from an unequal sharing of valence electrons. Because of this symmetry there is no region of unequal sharing and CO2 is anonpolar molecule

8 0

2 years ago

A 1.0-L buffer solution is 0.10 M in HF and 0.050 M in NaF. Which action destroys the buffer? (a) adding 0.050 mol of HCl (b) ad

Volgvan

Answer:

(a) adding 0.050 mol of HCl

Explanation:

A buffer is defined as the mixture of a weak acid and its conjugate base -or vice versa-.

In the buffer:

1.0L × (0.10 mol / L) = 0.10 moles of HF -Weak acid-

1.0L × (0.050 mol / L) = 0.050 moles of NaF -Conjugate base-

-The weak acid reacts with bases as NaOH and the conjugate base reacts with acids as HCl-

Thus:

(a) adding 0.050 mol of HCl: The addition of 0.050moles of HCl produce the reaction of 0.050 moles of NaF producing HF. That means after the reaction, all NaF is consumed and you will have in solution just the weak acid destroying the buffer.

(b) adding 0.050 mol of NaOH: The NaOH reacts with HF producing more NaF. Would be consumed just 0.050 moles of HF -remaining 0.050 moles of HF-. Thus, the buffer wouldn't be destroyed.

3 0

3 years ago

A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the

baherus [9]

Answer: 1. $9.08\times 10^{-6}$ moles

2. 90 mg

Explanation:

$O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)$

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus $4.54 \times 10^{-6}$ moles of ozone is removed by = $\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6}$ moles of sodium iodide.

Thus $9.08\times 10^{-6}$ moles of sodium iodide are needed to remove $4.54\times 10^{-6}$ moles of $O_3$

2. $\text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles$

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by = $\frac{2}{1}\times 0.0003=0.0006$ moles of sodium iodide.

Mass of sodium iodide= $moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg$ (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of $O_3$ .

3 0

2 years ago

Write the symbol for the monatomic ion that has a charge of 1– and the condensed electron configuration [ne]3s23p6.

Pani-rosa [81]

Answer is: the symbol is Cl.
[Ne ] 3s² 3p⁶ is electric configuration of noble gas argon, neon (Ne) has10 electrons plus 6 electrons in 3s and 3p orbitals. Neutral atom of monatomic ion that has a charge of 1– has one electron less than argon, so that atom (chlorine) has 17 electrons. Charge of 1- means one electron more for ion: 17 + 1 = 18.

3 0

2 years ago

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