Answer:
A. An element gains one or more electrons
Explanation:
Reduction is a chemical reaction that involves the gaining of electrons by one of the atoms involved in the reaction between two chemicals. The term refers to the element that
Answer:
See explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem.
Answer: True
Explanation:
Let's begin by explaining that the vision phenomenon depends on three elements: the observer, the object and the light source.
In addition, objects have pigments, which generally absorb more light than they reflect (they absorb certain wavelengths and reflect others). Therefore, the color that a given object seems to have depends on which parts of the visible electromagnetic spectrum are reflected and which parts are absorbed.
In this sense, the colours we see are in fact the wavelengths that are reflected or transmitted from the object. For example, a red object has that color because when it is illuminated whith white light, the pigments on this object abrsorb all the the wavelengths of the visible electromagnetic spectrum, except red. That is why red light is the only light that is reflected from the mentioned object.
For an aqueous solution of MgBr2, a freezing point depression occurs due to the rules of colligative properties. Since MgBr2 is an ionic compound, it acts a strong electrolyte; thus, dissociating completely in an aqueous solution. For the equation:
ΔTf<span> = (K</span>f)(<span>m)(i)
</span>where:
ΔTf = change in freezing point = (Ti - Tf)
Ti = freezing point of pure water = 0 celsius
Tf = freezing point of water with solute = ?
Kf = freezing point depression constant = 1.86 celsius-kg/mole (for water)
m = molality of solution (mol solute/kg solvent) = ?
i = ions in solution = 3
Computing for molality:
Molar mass of MgBr2 = 184.113 g/mol
m = 10.5g MgBr2 / 184.113/ 0.2 kg water = 0.285 mol/kg
For the problem,
ΔTf = (Kf)(m)(i) = 1.86(0.285)(3) = 1.59 = Ti - Tf = 0 - Tf
Tf = -1.59 celsius
Hydrochloric acid and sodium hydroxide
HCl + NaOh ----> NaCl + H2O
