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ratelena [41]
3 years ago
9

Why doesn’t a broken wineglass spontaneously fix itself, from a thermodynamic point of view?

Chemistry
2 answers:
deff fn [24]3 years ago
7 0

Answer:

C.Fixing a wineglass requires a large decrease in entropy.

Explanation:

Decrease in entropy is a non spontaneous process.  

Entropy is the measure of randomness or disorder. For a process to be spontaneous the disorder or the randomness should increase. In a spontaneous process entropy increase or becomes positive.  

A broken wine glass has more disorder than an unbroken glass. So a broken wine glass does not spontaneously fix itself as that would lead to a decrease in entropy.  

Anarel [89]3 years ago
4 0
C. Fixing a wineglass requires a large decrease in entropy.
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You put scruffy can run up to 2 meters/sec on his fastest days scruffy has a mass of 8 KG what is his maximum kinetic energy on
ale4655 [162]

Answer:

E = 16 J

Explanation:

We have,

You put scruffy can run up to 2 m/s on his fastest days scruffy has a mass of 8 kg

It is required to find the maximum kinetic energy on his fastest days. If v is the velocity, then kinetic energy is given by :

E=\dfrac{1}{2}mv^2

Plugging all the values,

E=\dfrac{1}{2}\times 8\times 2^2 \\\\E=16\ J

So, the maximum kinetic energy on his fastest day is 16 J.

6 0
4 years ago
How many atoms are in 3.89 moles of Cu?
AleksandrR [38]

Answer:

2.34×10^24

Explanation:

N=n×Na

N=3.89×(6.02×10^23)

N=2.34×+0^24 atoms of Cu

3 0
4 years ago
The work function of an element is the energy required to remove an electron from the surface of the solid element. The work fun
Anton [14]

Explanation:

The given data is as follows.

            Energy needed for 1 mole = 279.7 kJ = 279.7 \times \frac{1000 J}{1 kJ}

                                                       = 279700 J

Therefore, energy required for 1 atom will be calculated as follows.

                       \frac{279700}{6.022 \times 10^{22}}

                          = 4.645 \times 10^{-19} J

As relation between energy and wavelength is as follows.

                  E = \frac{hc}{\lambda}

where,    h = planck constant = 6.62 \times 10^{-34} Js

               c = speed of light = 3 \times 10^{8} m/s

           \lambda = wavelength

Therefore, putting given values into the above formula as follows.

                  E = \frac{hc}{\lambda}

      4.645 \times 10^{-19} J = \frac{6.62 \times 10^{-34} Js \times 3 \times 10^{8} m/s}{\lambda}  

              \lambda = 4.28 \times 10^{-7} m  

or,                         = 428 \times 10{-9} m

                             = 428 nm

Thus, we can conclude that the maximum wavelength of light that can remove an electron from an atom on the surface of lithium metal is 428 nm.

4 0
3 years ago
(a) Calculate the density of a 374.5-g sample of copper if it has a volume of 41.8 cm3. (b) A student needs 15.0 g of ethanol fo
o-na [289]

<u>Answer:</u>

<u>For a:</u> The density of the sample of copper is 8.96g/cm^3

<u>For b:</u> The volume of ethanol needed is 19.0 mL

<u>For c:</u> The mass of mercury is 340. grams

<u>Explanation:</u>

To calculate density of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}      ......(1)

  • <u>For a:</u>

Mass of copper = 374.5 g

Volume of copper = 41.8cm^3

Putting values in equation 1, we get:

\text{Density of copper}=\frac{374.5g}{41.8cm^3}\\\\\text{Density of copper}=8.96g/cm^3

Hence, the density of the sample of copper is 8.96g/cm^3

  • <u>For b:</u>

Mass of ethanol = 15.0 g

Density of ethanol = 0.789 g/mL

Putting values in equation 1, we get:

0.789g/mL=\frac{15.0g}{\text{Volume of ethanol}}\\\\\text{Volume of ethanol}=\frac{15.0g}{0.789g/mL}=19.0mL

Hence, the volume of ethanol needed is 19.0 mL

  • <u>For c:</u>

Volume of mercury = 25.0 mL

Density of mercury = 13.6 g/mL

Putting values in equation 1, we get:

13.6g/mL=\frac{\text{Mass of mercury}}{25.0mL}\\\\\text{Mass of mercury}=(13.6g/mL\times 25.0mL)=340.g

Hence, the mass of mercury is 340. grams

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3 years ago
To separate hard candie and marbles what is the efficient method
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MAke two piles and spread them apart
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