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sweet [91]
3 years ago
8

Rounding and math strategies

Mathematics
1 answer:
Otrada [13]3 years ago
5 0

304 would be the correct answer

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Yuki bought a drop–leaf kitchen table. The rectangular part of the table is a 1–by–5–foot rectangle with a semicircle at each en
Arada [10]

Answer:

iodfk

Step-by-step explanation:

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3 years ago
Which of these numbers 3,4,18,111,123,340,345,456,555 are multiples of 33 but not 9?
LUCKY_DIMON [66]

Answer:

4 and 132

Step-by-step explanation:

4 x 33 = 132

the numbers 4 and 132 have nothing to do with 9, no matter what way you look at them

i hope this helps :)

4 0
3 years ago
Which equation has a graph that is perpendicular to the graph of -x + 6y = -12?
serious [3.7K]

Answer:

c) 6x + y = -52  is required equation perpendicular to the given equation.

Step-by-step explanation:

If the equation is of the form    : y = mx  + C.

Here m = slope of the equation.

Two equations are said to be perpendicular if the product of their respective slopes is -1.

Here, equation 1 :  -x + 6y = -12

or, 6y = -12  + x

or, y = (x/6)  - 2

⇒Slope of line 1 = (1/6)

Now, for equation 2  to be  perpendicular:

Check for each equation:

a. x + 6y = -67       ⇒  6y = -67  - x

or, y = (-x/6)  - (67/6)      ⇒Slope of line 2 = (-1/6)

but \frac{1}{6} \times \frac{-1}{6}  \neq -1

b. x - 6y = -52   ⇒  -6y = -52  - x

or, y = (x/6)  + (52/6)      ⇒Slope of line 2 = (1/6)

but \frac{1}{6} \times \frac{1}{6}  \neq -1

c. 6x + y = -52    

or, y =y = -52  - 6x      ⇒Slope of line 2 = (-6)

\frac{1}{6} \times (-6)  =  -1

Hence, 6x + y = -52  is required equation 2.

d. 6x - y = 52  ⇒  -y = 52  - 6x

or, y = 6x   - 52      ⇒Slope of line 2 = (6)

but \frac{1}{6} \times 6  \neq -1

Hence,  6x + y = -52  is  the  only required equation .

3 0
3 years ago
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Are there any more numbers to this problem ? a picture of the data
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What is the second digit of pi?
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1. Pi is usually referred to as 3.14, so the answer is 1

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5. c) Irrational Numbers

I hope this helps! Let me know if you would like an explanation as to how I got the answers :)
5 0
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