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MakcuM [25]
4 years ago
15

Plz help me it’s a true or false question A shorter wire will allow electricity to

Physics
1 answer:
mr Goodwill [35]4 years ago
3 0

-- A shorter wire will allow electricity to  move through at a higher rate than a  longer wire . . . True, but "rate" is a poor way to say it. It should say "a higher current".  

-- A short, thick, cold wire is the best  conductor . . .  True

-- How well a material conducts current is an internal factor affecting resistance . . . True

-- If you double the length of a wire, you cut  the resistance in half . . . False. Double the length also means double the resistance.

-- If you double the thickness of a wire, you  cut the resistance in half . . . True

-- Superconductors have no measurable  resistance . . . True. They literally have NO resistance.

-- The higher the temperature of the  conductor, the lower the resistance . . . False. Higher temperature means higher resistance, for almost all conductors.

-- The resistance in a wire with less  thickness is less . . . False. We just said, up above  in Question-#5, "If you double the thickness of a wire, you  cut the resistance in half". Less thickness means more resistance. Just like a highway with fewer lanes.

-- Thickness, length, and temperature are  internal factors that affect resistance . . . False. They affect resistance, but they're external factors.

-- When a light is first switched on the light  bulb's filament has a lower resistance  than after it gives off light for awhile . . . True. Look back 3 questions from here, where it says "Higher temperature means higher resistance".

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A train at a constant 79.0 km/h moves east for 27.0 min, then in a direction 50.0° east of due north for 29.0 min, and then west
ivolga24 [154]

Answer:

Magnitude of avg velocity, |v_{avg}| = 18.9 km/h

\theta' = 56.85^{\circ}

Given:

Constant speed of train, v = 79 km/h

Time taken in East direction, t = 27 min = \frac{27}{60} h

Angle, \theta = 50^{\circ}

Time taken in 50^{\circ}east of due North direction, t' = 29 min =  \frac{29}{60} h

Time taken in west direction, t'' = 37 min =  \frac{27}{60} h

Solution:

Now, the displacement, 's' in east direction is given by:

\vec{s} = vt = 79\times \frac{27}{60} = 35.5\hat{i} km

Displacement in  50^{\circ} east of due North for 29.0 min is given by:

\vec{s'} = vt'sin50^{\circ}\hat{i} + vt'cos50^{\circ}\hat{j}

\vec{s'} = 79(\frac{29}{60})sin50^{\circ}\hat{i} + 79(\frac{29}{60})cos50^{\circ}\hat{j}

\vec{s'} = 29.25\hat{i} + 24.54\hat{j} km

Now, displacement in the west direction for 37 min:

\vec{s''} = - vt''hat{i} = - 79\frac{37}{60} = - 48.72\hat{i} km

Now, the overall displacement,

\vec{s_{net}} = \vec{s} + \vec{s'} + \vec{s''}

\vec{s_{net}} = 35.5\hat{i} + 29.25\hat{i} + 24.54\hat{j} - 48.72\hat{i}

\vec{s_{net}} =  16.03\hat{i} + 24.54\hat{j} km

(a) Now, average velocity, v_{avg} is given:

v_{avg} = \frac{total displacement, \vec{s_{net}}}{total time, t}

v_{avg} = \frac{16.03\hat{i} + 24.54\hat{j}}{\frac{27 + 29 + 37}{60}}

v_{avg} = 10.34\hat{i} + 15.83\hat{j}) km/h

Magnitude of avg velocity is given by:

|v_{avg}| = \sqrt{(10.34)^{2} + (15.83)^{2}} = 18.9 km/h

(b) angle can be calculated as:

tan\theta' = \frac{15.83}{10.34}

\theta' = tan^{- 1}\frac{15.83}{10.34} = 56.85^{\circ}

6 0
4 years ago
What can change of matter from one state to another state?
Anna35 [415]

Answer:

answer is Heating

Explanation:

take a solid and heat it it will become a liquid

8 0
3 years ago
A round pipe of varying diameter carries petroleum from a wellhead to a refinery. At the wellhead, the pipe's diameter is 57.3 c
Mashcka [7]

Answer with Explanation:

We are given that

Diameter of pipe,d_1=0.573 m

v_1=13.5 m/s

v_2=5.83 m/s

Volume flow rate of the petroleum along the pipe=Q_{refinery}=A_1v_1=v_(\frac{\pi d^2_1}{4})

Q_{refinery}=13.5\times (\pi\times \frac{0.573)^2}{4})=3.48 m^3/s

By equation of continuity

A_1v_1=A_2v_2

\frac{\pi d^2_1}{4}v_1=\frac{\pi d^2_2}{4}v_2

d^2_2=\frac{v_1}{v_2}d^2_1

d_2=\sqrt{\frac{v_1}{v_2}}d_1

d_2=0.573\sqrt{\frac{13.5}{5.83}}

d_2=0.87 m

d_2=0.87\time 100=87 cm

1 m=100 cm

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