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MakcuM [25]
3 years ago
15

Plz help me it’s a true or false question A shorter wire will allow electricity to

Physics
1 answer:
mr Goodwill [35]3 years ago
3 0

-- A shorter wire will allow electricity to  move through at a higher rate than a  longer wire . . . True, but "rate" is a poor way to say it. It should say "a higher current".  

-- A short, thick, cold wire is the best  conductor . . .  True

-- How well a material conducts current is an internal factor affecting resistance . . . True

-- If you double the length of a wire, you cut  the resistance in half . . . False. Double the length also means double the resistance.

-- If you double the thickness of a wire, you  cut the resistance in half . . . True

-- Superconductors have no measurable  resistance . . . True. They literally have NO resistance.

-- The higher the temperature of the  conductor, the lower the resistance . . . False. Higher temperature means higher resistance, for almost all conductors.

-- The resistance in a wire with less  thickness is less . . . False. We just said, up above  in Question-#5, "If you double the thickness of a wire, you  cut the resistance in half". Less thickness means more resistance. Just like a highway with fewer lanes.

-- Thickness, length, and temperature are  internal factors that affect resistance . . . False. They affect resistance, but they're external factors.

-- When a light is first switched on the light  bulb's filament has a lower resistance  than after it gives off light for awhile . . . True. Look back 3 questions from here, where it says "Higher temperature means higher resistance".

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g How many diffraction maxima are contained in a region of the Fraunhofer single-slit pattern, subtending an angle of 2.12°, for
lbvjy [14]

Answer:

2

Explanation:

We know that in the Fraunhofer single-slit pattern,

maxima is given by

a\text{sin}\theta=\frac{2N+1}{2}\lambda

Given values

θ=2.12°

slit width a= 0.110 mm.

wavelength λ= 582 nm

Now plugging values to calculate N we get

0.110\times10^{-3}\text{sin}2.12=(\frac{2N+1}{2})582\times10^{-9}

Solving the above equation we get

we N= 2.313≅ 2

4 0
3 years ago
The three forces acting on a hot-air balloon that is moving vertically are its weight, the force due to air resistance and the u
irinina [24]

Explanation :

The forces acting on hot- air balloon are:

Weight, (W)

Force due to air resistance, (F)

Upthrust force, (U)

Its weight W is acting in downward direction. The upthrust force U acts in upward direction. When the balloon is moving upward, the air resistance is in downward and vice versa.

In this case, the hot-air balloon descends vertically at constant speed.

so, a=0

and F=ma=0

so, W = F + U ....................(1)

when it is ascending let the weight that it is releasing is R, so

(W-R) + F = U..........(2)

solving equation (1) and (2)

(W-R)+F=W-F

R=2F            

2F is the weight of material that must be released from the balloon so that it ascends vertically at the same constant speed.

7 0
3 years ago
Read 2 more answers
PLEASE HELP ME WITH THIS ONE QUESTION
Marizza181 [45]

Answer:

c) 2.02 x 10^16 nuclei

Explanation:

The isotope decay of an atom follows the equation:

ln[A] = -kt + ln[A]₀

<em>Where [A] is the amount of the isotope after time t, k is decay constant, [A]₀ is the initial amount of the isotope</em>

[A] = Our incognite

k is constant decay:

k = ln 2 / Half-life

k = ln 2 / 4.96 x 10^3 s

k = 1.40x10⁻⁴s⁻¹

t is time = 1.98 x 10^4 s

[A]₀ = 3.21 x 10^17 nuclei

ln[A] = -1.40x10⁻⁴s⁻¹*1.98 x 10^4 s + ln[3.21 x 10^17 nuclei]

ln[A] = 37.538

[A] = 2.01x10¹⁶ nuclei remain ≈

<h3>c) 2.02 x 10^16 nuclei</h3>
7 0
2 years ago
In the final situation below, the 8.0 kg box has been launched with a speed of 10.0 m/s across a frictionless surface. Find the
Murljashka [212]

Answer:

the energy of the spring at the start is 400 J.

Explanation:

Given;

mass of the box, m = 8.0 kg

final speed of the box, v = 10 m/s

Apply the principle of conservation of energy to determine the energy of the spring at the start;

Final Kinetic energy of the box = initial elastic potential energy of the spring

K.E = Ux

¹/₂mv² = Ux

¹/₂ x 8 x 10² = Ux

400 J = Ux

Therefore, the energy of the spring at the start is 400 J.

8 0
3 years ago
If a transformer has 5000 turns on the primary circuit, 3000 turns on
nikitadnepr [17]
The answer is C , you’re welcome
3 0
3 years ago
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