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Aneli [31]
3 years ago
6

A charge -353e is uniformly distributed along a circular arc of radius 5.30 cm, which subtends an angle of 48°. What is the line

ar charge density along the arc?
Physics
1 answer:
vladimir2022 [97]3 years ago
4 0

Answer:

- 1.3 x 10⁻¹⁵ C/m

Explanation:

Q = Total charge on the circular arc = - 353 e = - 353 (1.6 x 10⁻¹⁹) C = - 564.8 x 10⁻¹⁹ C

r = Radius of the arc = 5.30 cm = 0.053 m

θ = Angle subtended by the arc = 48° deg = 48 x 0.0175 rad = 0.84 rad        (Since 1 deg = 0.0175 rad)

L = length of the arc

length of the arc is given as

L = r θ

L = (0.053) (0.84)

L = 0.045 m

λ = Linear charge density

Linear charge density is given as

\lambda =\frac{Q}{L}

Inserting the values

\lambda =\frac{-564.8\times 10^{-19}}{0.045}

λ = - 1.3 x 10⁻¹⁵ C/m

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large cylindrical water tank is mounted on a platform with its central axis vertical. The water level is 3.75 m above the base o
eduard

Answer:

0.0000333 m³/s

Explanation:

using Bernoulli's equation

P1 + 1/2ρv1² + ρh1g = P2 + 1/2ρv2² + ρh2g

P1 = P2 both are atmospheric pressure; they cancel out

1/2ρv1² + ρh1g = 1/2ρv2² + ρh2g divide both side with ρ (rho)

1/2v1² + h1g = 1/2v2² +h2g

collect the like terms

h1g - h2g = 1/2v2² + 1/2v1²

multiply both side by 2 and take g out from the left equation

2g(h1 - h2) = v2² + v1² where v1 is approximately 0 assuming the surface of the tank is large

v2² = 2g(h1 - h2)

take square root of both sides

v2 = √2g(h1 - h2)

h1 = 3.75 + 6.5 = 10.25

h2 = 6.5

v2 = √2g(h1 - h2) = √ (2×9.81× (10.25 - 6.5)) = 8.6 m/s

Volume in m³/s = A × v where A is the area of the hole  and the radius of the hole = 2.22 mm / 2 (where 2.22 mm is the diameter of the hole) = 1.11 mm and  1.11mm / 1000 to convert it to meters

Area of the hole ( assuming it is a circle) = πr² = 3.142× (1.11/1000)²

Area = 0.00000387 m²

Volume in M³/s = 0.00000387 × 8.6 = 0.0000333 m³/s

8 0
3 years ago
The term fetus completes which of the following lists to show the correct order of development?
netineya [11]
The answer is C............
8 0
3 years ago
Two long, parallel wires are separated by a distance of 2.00 cm . The force per unit length that each wire exerts on the other i
RUDIKE [14]

Answer:

a) current in the second wire is 5.60A

b) opposite directions

Explanation:

a) We need to find the current of wire, the magnitude of the force per unit length between the two wires carrying current I and I¹ is given by

\frac{F}{L} = \frac{U_0I^1}{2\pi r} \\\\I^1 = \frac{F2\pi r}{LU_0I}

= (3.6 * 10^-^5)\frac{2\pi (0.02)}{4\pi * 10^-^7)(0.64)} \\= 5.60A

b) knowing that for a two parallel conductor carrying current in the same direction attracts each other, and for a two parallel conductors carrying carying current in opposite direction repels eachother.

therefore, since the two wire repel each other then the current in the second wire must flow in the opposite direction of the current in the first wire.

7 0
4 years ago
A bowling bowl is thrown off the top of a building. Determine distance the ball has fallen after falling for 3.0 s. Remember, th
Zanzabum

d = distance the bowling ball has fallen = ?

g = acceleration due to gravity acting on the ball by earth = 9.8 m/s²

t = time of fall for the ball = 3.0 s

distance the ball has fallen is given as

d = (0.5) g t²

inserting the above values in the equation above

d = (0.5) (9.8 m/s²) (3.0 s)²

d = (0.5) (9.8 m/s²) (9.0 s²)

d = (4.9 m/s²) (9.0 s²)

d = 44.1 m

hence the distance fallen by the ball comes out to be 44.1 m

7 0
4 years ago
Julie drives 100 mi to Grandmother's house. On the way to Grandmother's, Julie drives half the distance at 20 mph and half the d
Gnoma [55]

Answer:

On the way to grandmother´s, the average speed was 30 mph. On the way back, the average speed was 40 mph.

Explanation:

The average speed is given by the variation of the position over time.

Mathematically:

ΔX / Δt = v

where:

ΔX = distance (final position - initial position)

Δt = time (final time - initial time)

v = speed

On the way to Grandmother´s, we can calculate how much time Julie drove at each speed:

ΔX / Δt = v

ΔX / v = Δt

50 mi / 20 mph = 2.5 h

In the same way, we can calculate how much time she drove at 60 mph:

50 mi / 60 mph = 0.83 h

In total, she drove a distance of 100 mi in (2.5 h + 0.83 h) 3.33 h. Then, the average speed on the way to Grandmother´s was:

<u>ΔX / Δt = v = 100 mi / 3.33 h = 30 mph</u>

In the return trip, we do not know the distance nor the time that she drove at each speed, but we know that for each part of the trip, the time is the same (Δt)  and we also know that the total distance is 100 mi and the total time is 2Δt:

v1 = ΔX1 / Δt

v2 = ΔX2 / Δt

ΔX2 + ΔX1  = 100

where

v1 = speed during the first part of the trip (20 mph)

v2 = speed during the second part of the trip (60 mph)

ΔX1 = distance driven at 20 mph

ΔX2 = distance driven at 60 mph

Δt = time

If we divide v2/v1, we will get:

v2/v1 = (ΔX2 / Δt) / (ΔX1 / Δt)

60 mph / 20 mph = ΔX2 / ΔX1

3 = ΔX2 / ΔX1

3ΔX1 = ΔX2

Then we can replace ΔX2 for 3ΔX1 in this equation:

ΔX2 + ΔX1  = 100 mi

3ΔX1 + ΔX1 = 100 mi

4ΔX1 = 100 mi

ΔX1 = 25 mi

And now, we can solve Δt from the equation of v1:

v1 = ΔX1 / Δt

Δt = ΔX1 / v1 = 25 mi / 20 mph = 1.25 h

The average speed on the return trip is then:

<u>v = 100 mi / 2Δt = 100 mi / 2.5 h = 40mph</u>

8 0
4 years ago
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