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fiasKO [112]
3 years ago
10

You ride your bicycle into the country side on a bike path. You travel 6 kilometers the first hour, 3 kilometers the second hour

, 6 the third what is your average speed?
Physics
1 answer:
aleksandrvk [35]3 years ago
8 0
6+3+6= 15 / 3 = 5KPH
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An electron initially has a speed 16 km/s along the x-direction and enters an electric field of strength 27 mV/m that points in
weqwewe [10]

Answer:

a)t=1.4\times 10^{-5}\ s

b)S= 46.4 cm

Explanation:

Given that

Velocity = 16 Km/s

V= 16,000 m/s

E= 27 mV/m

E=0.027 V/m

d= 22.5 cm

d= 0.225 m

a)

lets time taken by electron is t

d = V x t

0.225 = 16,000 t

t=1.4\times 10^{-5}\ s

b)

We know that

F = m a = E q                    ------------1

Mass of electron ,m

m=9.1\times 10^{-31}\ kg

Charge on electron

q=1.6\times 10^{-19}\ C

So now by putting the values in equation 1

a=\dfrac{E q}{m}

a=\dfrac{1.6\times 10^{-19}\times 0.027}{9.1\times 10^{-31}}\ m/s^2

a=4.74\times 10^{9}\ m/s^2

S= ut+\dfrac{1}{2}at^2

Here initial velocity u= 0 m/s

S= \dfrac{1}{2}\times 4.74\times 10^{9}\times (1.4\times 10^{-5})^2\ m

S=0.464 m

S= 46.4 cm

S is the deflection of electron.

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