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klasskru [66]
3 years ago
10

An old woman is worried about time. She walks at a rate of 2 meters per second and travels a

Physics
2 answers:
frutty [35]3 years ago
6 0

Answer:

227 seconds.

Explanation:

Speed is equal to distance divided by time. s = d/t

We can rearrange this algebraically to solve for the time it will take to cover a certain distance at a certain speed. Time is equal to distance divided by speed.  t = d/s

Then we substiture our known values for the variables and solve for our unknown.

t = 454m / 2m/s = 227s

larisa [96]3 years ago
3 0

Answer:

If the lady is traveling 2 meters per second and she travels 454 meters then you will have to divide 454 by 2 to get the amount of time she walked.

454 divided by 2 = 227

This means that the lady traveled for 227 seconds or about 3.78 minutes.

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A mule pulls a cart of milk 10 meters with a force of 50 Newton's.Calculate the work done by a mule
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Work = Force x Distance

Assuming that this work is being done parallel to the displacement that is, but under that assumption:

W = (50)(10)

W = 500 J

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a gym consists of a rectangular region with a semi-circle on each end. if the perimeter of the room is to be a 200 m running tra
Nikolay [14]

The dimensions of the rectangle are:

l = 50 m

b = 100/\pi m

<h3>What is a perimeter in math?</h3>

The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides.

<h3>How do we find a perimeter of a rectangle?</h3>

The perimeter of a rectangle,denoted by P is given by the formula, P=2l+2b, where l is the length and b is the breadth of the rectangle.

<h3>Given:</h3>

As per the question:

Perimeter of the room is given as P = 200 m

The region is rectangular having a semicircle at each end.

Now,

Let 'l' be the length of the rectangle, 'b' be its breadth and 'r' be the radius of the semi-circle at each end.

Then, Area of the given rectangle, A = lb

Perimeter of the room, P is =\pi r+l+\pi r+l=2\pi r+2l=\pi b+2l

Therefore,  \pi b+2l=200

b=(200-2l)/\pi

Now,

Area, A = l(200-2l)/\pi=(200l-2l^{2} )/\pi

Now, differentiate A w.r.t l:

Again differentiating w.r.t 'l', we get:

d^{2} A/dl^{2} =-4l/\pi< 0

Thus we get maximum are when dA/dl=0

Therefore,

(200-4l)/\pi=0

l = 50 m

Now, from

\pi b+2l=200

\pi b=200-2*50

b=100/\pi

r=b/2=50/\pi

To know more about area of a recatangle, visit the link

brainly.com/question/20693059

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