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VMariaS [17]
4 years ago
6

Match each processes with the correct transfer of energy.

Chemistry
1 answer:
sveticcg [70]4 years ago
7 0

freezing-energy lost (exothermic)

sublimation-energy gain (endothermic)

evaporation- energy gain(endothermic)

Melting- energy gain(endothermic)

deposition- energy lost(exothermic)

condensation-energy lost(exothermic)

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The composition of a liquid-phase reaction 2A - B was monitored spectrophotometrically. The following data was obtained: t/min 0
o-na [289]

Answer:

1) The order of the reaction is of FIRST ORDER

2)   Rate constant k = 5.667 × 10 ⁻⁴

Explanation:

From the given information:

The composition of a liquid-phase reaction 2A - B was monitored spectrophotometrically.

liquid-phase reaction 2A - B signifies that the reaction is of FIRST ORDER where the rate of this reaction is directly proportional to the concentration of A.

The following data was obtained:

t/min                    0         10         20          30             40          ∞

conc B/(mol/L)    0       0.089    0.153     0.200       0.230    0.312

For  a first order reaction:

K = \dfrac{1}{t} \ In ( \dfrac{C_{\infty} - C_o}{C_{\infty} - C_t})

where :

K = proportionality  constant or the rate constant for the specific reaction rate

t = time of reaction

C_o = initial concentration at time t

C _{\infty} = final concentration at time t

C_t = concentration at time t

To start with the value of t when t = 10 mins

K_1 = \dfrac{1}{10} \ In ( \dfrac{0.312 - 0}{0.312 - 0.089})

K_1 = \dfrac{1}{10} \ In ( \dfrac{0.312 }{0.223})

K_1 =0.03358 \  min^{-1}

K_1 \simeq 0.034 \  min^{-1}

When t = 20

K_2= \dfrac{1}{20} \ In ( \dfrac{0.312 - 0}{0.312 - 0.153})

K_2= 0.05 \times  \ In ( 1.9623)

K_2=0.03371 \ min^{-1}

K_2 \simeq 0.034 \ min^{-1}

When t = 30

K_3= \dfrac{1}{30} \ In ( \dfrac{0.312 - 0}{0.312 - 0.200})

K_3= 0.0333 \times  \ In ( \dfrac{0.312}{0.112})

K_3= 0.0333 \times  \ 1.0245

K_3 = 0.03412 \ min^{-1}

K_3 = 0.034 \ min^{-1}

When t = 40

K_4= \dfrac{1}{40} \ In ( \dfrac{0.312 - 0}{0.312 - 0.230})

K_4=0.025 \times  \ In ( \dfrac{0.312}{0.082})

K_4=0.025 \times  \ In ( 3.8048)

K_4=0.03340 \ min^{-1}

We can see that at the different time rates, the rate constant of k_1, k_2, k_3, and k_4 all have similar constant values

As such :

Rate constant k = 0.034 min⁻¹

Converting it to seconds ; we have :

60 seconds = 1 min

∴

0.034 min⁻¹ =(0.034/60) seconds

= 5.667 × 10 ⁻⁴ seconds

Rate constant k = 5.667 × 10 ⁻⁴

4 0
3 years ago
What is the atomic number of an atom that has 3 protons and 4 neutrons?
erik [133]
Tha atomic number of an atom that has 3 protons and 4 neutrons is 3. It's the lithium
5 0
3 years ago
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Which skeleton equation represents a neutralization reaction? Mg + O2 MgO AlCl3 Al + Cl2 Li + HNO3 H2 + LiNO3 HBr + LiOH LiBr +
creativ13 [48]
Neutralization reaction is the reaction between acid and base.
There the neutralization reaction is:

HBr + LiOH ----------> LiBr + H2O.

Hope this helps!
5 0
3 years ago
Read 2 more answers
Explain the laws of thermodynamics and why they matter.
creativ13 [48]
Following are the laws of thermodynamics, with suitable example. 

1st Law of thermodynamics: 
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2nd Law of thermodynamics:
2nd law of thermodynamics deals with entropy change associated with system. It is stated as '</span><span> entropy of any isolated system always increases'. According to this law, the system tries to maximize entropy. System with higher entropy is more stable than system with lower entropy. For instance, at room temperature, ice melts into water, because water has higher entropy than ice. It may be noted that entropy is measure of disorder in system. Thus, higher the disorder in system, greater is the entropy.

3rd Law of thermodynamics:
3rd law of thermodynamics also deal with entropy change in system. According to this law, </span><span>entropy of a system approaches a constant value as the temperature approaches absolute zero. This means that, as the temperature decreases, randomness in system decreases and finally at 0K, system is in highly order state, hence ideally system must have zero entropy. However, there is always some residual entropy present in system even at 0K, due structural orientation of molecules.  </span>
7 0
3 years ago
Which will dissolve faster in water rock salt or granulated salt
Sladkaya [172]

Answer:

Salt!!!

Explanation:

7 0
3 years ago
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