Question

Determine the volume, in liters, occupied by 0.015 molecules of oxygen at STp?

Answer 1

5.58 X $10^{-25}$ Litres is the volume, in liters, occupied by 0.015 molecules of oxygen at STP.

Explanation:

Data given:

molecules of oxygen = 0.015

number of moles of oxygen =?

temperature at STP = 273  K

Pressure at STP = 1 atm

volume = ?

R (gas constant) = 0.08201 L atm/mole K

to convert molecules to moles,

number of moles = $\frac{molecules}{Avagadro's number}$

number of moles = 2.49 x $10^{-26}$

Applying the ideal gas law since the oxygen is at STP,

PV = nRT

rearranging the equation:

V = $\frac{nRT}{P}$

putting the values in the rearranged equation:

V = $\frac{2.49 X10^{-26} X 0.08201 X 273}{1}$

V = 5.58 X $10^{-25}$ Litres.