Answer: -345.2 KJ
Explanation: As we know that ,dG=dH-TdS
T=25+273=298 K
dG= -356 x1000-298(-36)= -356000+10728
=-345272 j
= -345.2 KJ
Answer:
σ = 4.998 E-4 C/m²
Explanation:
- 1 Coulomb (C) ≡ 6.241509 E18 electrons (e)
∴ # elect = 6.24 E14 elect
charge (Q):
⇒ Q = (6.24 E14 elect)/( 1 C /6.241509 E18 elect) = 9.998 E-5 C
charge density (σ):
∴ surface area (S) = 0.2 m²
⇒ σ = ( 9.998 E-5 C ) / ( 0.2 m²)
⇒ σ = 4.998 E-4 C/m²
Why did you post this again? Because you're lazy and wanted people to not see my post? Once again, ONE QUESTION AT A TIME. We're here to help you with a tough question or work you through it, not do all your homework.
Answer:
<h3>The answer is 40.96%</h3>
Explanation:
The percentage error of a certain measurement can be found by using the formula
From the question
actual density = 2.49g/mL
error = 2.49 - 1.47 = 1.02
We have
We have the final answer as
<h3>40.96 %</h3>
Hope this helps you
KI-starch paper allows the detection of strong oxidizers such as nitrite. It is used here to control diazotization of 4-nitroaniline. Nitrite oxidizes potassium iodide in order to form elemental iodine which reacts with starch to a blue-violet complex. With KI-starch paper, enough sodium nitrite is added to produce nitrous acid, which <span>then will react with 4-nitroaniline to form a diazonium salt.</span>
