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3 years ago

How many miles of NaOH will completely react with 10.0 mL of 1.0 M HCl?

2 answers:

6 0

The reaction between 1 mole of NaOH and 1 mole of HCl creates 1 mole of NaCl and 1 mole of water. Meaning that the moles of HCl needs to equal that of NaOH for the solution to be considered equalized. That being said, you first need to find the numbers miles of HCl by multiplying the volume by the molarity to get 0.01 moles HCl. (1Mx0.01L=0.01). That means that you need 0.01 moles of NaOH. I hope that helps. Let me know if anything is unclear.

Andru [333]3 years ago

6 0

V = 10.0 mL / 1000 = 0.01 L

Molarity = number of moles / volume

1.0 = n / 0.01

n = 1.0 * 0.01

n = 0.01 mols of HCl

hope this helps!

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Which of the following halogens has the weakest attraction for electrons?

Leokris [45]

Answer:

Explanation:

Among the halogens given in this problem, iodine has the lowest attraction for electrons.

This property is known as electronegativity.

Electronegativity is expressed as the relative tendency with which the atoms of the element attracts valence electrons in a chemical bond.

As you go down the periodic group the electronegativity decreases.
The most electronegative element on the periodic table is fluorine.
Down the group, iodine is the least electronegative
This is due to the large size of its atom.

4 0

3 years ago

Barium sulfate is made by the following reaction.

ipn [44]

Answer:

%age Yield = 96 %

Explanation:

The balance chemical equation for given double replacement reaction is,

Ba(NO₃)₂ + Na₂SO₄ → BaSO₄ + 2 NaNO₃

Step 1: Calculate moles of Ba(NO₃)₂:

Moles = Mass / M.Mass

Moles = 75.1 g / 261.33 g/mol

Moles = 0.2873 moles of Ba(NO₃)₂

Step 2: Find out moles of BaSO₄ formed:

According to balance chemical equation,

1 mole of Ba(NO₃)₂ produced = 1 mole of BaSO₄

So,

0.2873 moles of Ba(NO₃)₂ will produce = X moles of BaSO₄

Solving for X,

X = 0.2873 mol × 1 mol / 1 mol

X = 0.2873 moles of BaSO₄

Step 3: Calculate Theoretical Mass of BaSO₄:

Mass = Moles × M.Mass

Mass = 0.2873 mol × 233.38 g/mol

Mass = 67.07 g of BaSO₄

Step 4: Calculate %age Yield as:

Theoretical Yield = 67.07 g

Actual Yield = 64.4 g

%age Yield = ???

Formula Used:

%age Yield = (Actual Yield ÷ Theoretical Yield) × 100

Putting Values,

%age Yield = (64.4 g ÷ 67.07 g) × 100

%age Yield = 96.01 % ≈ 96 %

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3 years ago

Cuales elementos tienen solo un electrón de valencia

aleksley [76]

Answer:

En el caso del sodio, la valencia es 1, ya que tiene un solo electrón de valencia, si pierde un electrón se queda con el último nivel completo.

Explanation:

Grupo de la tabla periódica Electrones de valencia

Grupo 14 (IV) (Grupo del carbono) 4

Grupo 15 (V) (Grupo del nitrógeno ) 5

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3 years ago

Write the net ionic equation for the precipitation reaction that occurs when aqueous solutions of chromium(III) bromide and pota

expeople1 [14]

Explanation:

An ionic equation will be the one in which all the participating species will be present as ions.

The given reaction will be as follows.

$CrBr_{3} + K_{2}CO_{3} \rightarrow Cr_{2}(CO_{3})_{3}(s) + KBr$

Balancing this equation by multiplying $CrBr_{3}$ by 2 and $K_{2}CO_{3}$ by 3 on reactant side. Whereas multiply KBr by 6 on product side.

$2CrBr_{3} + 3K_{2}CO_{3} \rightarrow Cr_{2}(CO_{3})_{3}(s) + 6KBr$

Hence, the net ionic equation will be as follows.

$2Cr^{3+}(aq) + 3CO^{2-}_{3}(aq) + 6K^{+} + 6Br^{-} \rightarrow Cr_{2}(CO_{3})_{3}(s) + 6K^{+} + 6Br^{-}$

As both $K^{+}$ and $Br^{-}$ are spectator ions. Hence, the net ionic equation will be as follows.

$2Cr^{3+}(aq) + 3CO^{2-}_{3}(aq) \rightarrow Cr_{2}(CO_{3})_{3}(s)$

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3 years ago

Which of the following will neutralize an acid?

pochemuha

LiOH is going to neutralize the acid because it’s a base

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3 years ago