1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bearhunter [10]
4 years ago
14

I don't know how to do this. Working on #2

Physics
1 answer:
Mashcka [7]4 years ago
5 0
-- You know how much work the bow does on the arrow.

         Work = (force) x (distance) =  (65 N) x (0.9 m)

-- THAT's the energy the arrow got from the bow, so
THAT's the kinetic energy the arrow has as it leaves the bow.

       KE = (1/2) (m) (speed)²

       so     (1/2) (0.075 kg) (speed)²  =  (65 N) x (0.9 m)

The speed is the only thing left unknown in this mess.
I'm sure you can handle it from here, and find the speed.       
 
You might be interested in
A man walking on a tightrope carries a long a pole which has heavy items attached to the two ends. If he were to walk the tight-
katen-ka-za [31]

Answer:

 I_weight = M L²

this value is much larger and with it it is easier to restore balance.I

Explanation:

When man walks a tightrope, he carries a linear velocity, this velocity is related to the angular velocity by

            v = w r

For man to maintain equilibrium needs the total moment to be zero

             ∑τ = I α

              S  τ = 0

The forces on the home are the weight of the masses, the weight of the man and the support on the rope, the latter two are zero taque the distance to the center of rotation is zero.

Therefore the moment of the masses and the open is the one that must be zero.

If the man carries only the bar, we could approximate it by two open one on each side of the axis of rotation formed by the free of the rope

              I = ⅓ m L² / 4

As the length of half the length of the bar and the mass of the bar is small, this moment is small, therefore at the moment if there is some imbalance it is difficult to recover.

If, in addition to the opening, each of them carries a specific weight, the moment of inertia of this weight is

             I_weight = M L²

this value is much larger and with it it is easier to restore balance.

5 0
3 years ago
What is it that makes a magnet different from a piece of iron that is not mangetic?​
Alisiya [41]

Answer:

Under normal conditions, a magnetic material like iron doesn't behave like a magnet because the domains don't have a preferred direction of alignment. On the other hand, the domains of a magnet (or a magnetized iron) are all aligned in s specific direction.

7 0
3 years ago
A phosphodiester bond is used to:
bonufazy [111]

Answer:

A. Join glycerol to fatty acids

Explanation:

I majored in Physics.

4 0
3 years ago
Read 2 more answers
Right answer gets brainlist
ira [324]
Numberrrr 1 Inertiaaaaa
3 0
3 years ago
A point charge q is located at the center of a spherical shell of radius a that has a charge −q uniformly distributed on its sur
muminat

Answer:

a) E = 0

b) E =  \dfrac{k_e \cdot q}{ r^2 }

Explanation:

The electric field for all points outside the spherical shell is given as follows;

a) \phi_E = \oint E \cdot  dA =  \dfrac{\Sigma q_{enclosed}}{\varepsilon _{0}}

From which we have;

E \cdot  A =  \dfrac{{\Sigma Q}}{\varepsilon _{0}} = \dfrac{+q + (-q)}{\varepsilon _{0}}  = \dfrac{0}{\varepsilon _{0}} = 0

E = 0/A = 0

E = 0

b) \phi_E = \oint E \cdot  dA =  \dfrac{\Sigma q_{enclosed}}{\varepsilon _{0}}

E \cdot  A  = \dfrac{+q }{\varepsilon _{0}}

E  = \dfrac{+q }{\varepsilon _{0} \cdot A} = \dfrac{+q }{\varepsilon _{0} \cdot 4 \cdot \pi \cdot r^2}

By Gauss theorem, we have;

E\oint dS =  \dfrac{q}{\varepsilon _{0}}

Therefore, we get;

E \cdot (4 \cdot \pi \cdot r^2) =  \dfrac{q}{\varepsilon _{0}}

The electrical field outside the spherical shell

E =  \dfrac{q}{\varepsilon _{0} \cdot (4 \cdot \pi \cdot r^2) }= \dfrac{q}{4 \cdot \pi \cdot \varepsilon _{0} \cdot r^2 }=  \dfrac{q}{(4 \cdot \pi \cdot \varepsilon _{0} )\cdot r^2 }

k_e=  \dfrac{1}{(4 \cdot \pi \cdot \varepsilon _{0} ) }

Therefore, we have;

E =  \dfrac{k_e \cdot q}{ r^2 }

5 0
3 years ago
Other questions:
  • A girl is whirling a ball on a string around her head in
    6·1 answer
  • What is the most accurate description of the plasma state of matter
    5·1 answer
  • The most recent evidence supporting the theory of plate tectonics would include A) GPS monitoring of plate speeds and movements.
    12·1 answer
  • Which part of the iceberg displaces water equal in weight to the buoyant force
    6·2 answers
  • A pursuit spacecraft from the planet Tatooine is attempting to catch up with a Trade Federation cruiser. As measured by an obser
    11·2 answers
  • M84, M87, and NGC 4258 all have accretion disks around their central black holes for which the rotational velocities have been m
    12·1 answer
  • (need help) " You make the following measurements of an object: 42kg and 22m^3. What would be the objects density be? Show work
    10·1 answer
  • A man pushes a lawn mower with a force of 25 newtons. The lawn mower has a mass of 17 kilograms and the handle makes an angle of
    6·1 answer
  • Accurate _______ is needed in a valid experiment.<br><br> Hurry, I need help.
    5·1 answer
  • Is my answer correct?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!