The specific heat capacity of sand is much less than water because of which sands require less energy to cool down and similarly less energy to be heated... because of this it feels like sands absrob heat faster than water
Answer:
D. It is limited to situations that involve aqueous solutions or specific compounds.
Explanation:
An Arrhenius acid is a substance that increases the concentration of H3O or H+ when dissolved in water. An Arrhenius base is a substance that increases the concentration of OH- when dissolved in water. These definitions tell us that D is indeed limited to situations that involve aqueous solutions or specific compounds, as aqueous means something that's dissolved in water.
A is wrong because the Bronsted-Lowry interpretation has a wider range of applications. Bronsted-Lowry acids and bases don't even need to be aqueous, so it is not limited to just aqueous solutions. They include any substance that can donate or accept a H+.
B is wrong because A is wrong. A and B basically say the same thing, that the Arrhenius interpretation has a wider range of applications than the Bronsted-Lowry interpretation.
C is wrong because the definition of an Arrhenius base is any substance that increases the concentration of OH-, or hydroxide ions. C completely counters this statement.
Here's photo for proof incase you're doubtful of my answer & explanation. Please click the heart if it helped.
Let's check Electronic configuration of N in ground state


In hydrogen case

Hence Hybridization


Structure is tetrahedral .
Spare way:-
- Bond pairs==3=>Bonding electrons=6
- Lone pair=1=>Anti bonding electrons=2
Hybridization
![\\ \sf\longmapsto \dfrac{1}{2}[\sigma+\sigma *]](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cdfrac%7B1%7D%7B2%7D%5B%5Csigma%2B%5Csigma%20%2A%5D)
![\\ \sf\longmapsto \dfrac{1}{2}[6+2]](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cdfrac%7B1%7D%7B2%7D%5B6%2B2%5D)
![\\ \sf\longmapsto \dfrac{1}{2}[8]](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cdfrac%7B1%7D%7B2%7D%5B8%5D)

- sp3 Hybridization
- Shape-Tetrahedral .
Explanation:
This reaction is in equilibrium and would hence obey lechatelier's principle. This principle states that whenever a system at equilibrium undergoes a change, it would react in way so as to annul that change.
Since it is an endothermic reaction, increasing the temperature would cause the reaction to shift towards the right.
This means that it favours product formation and more of the product would be formed.