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kirill115 [55]
3 years ago
13

Rock whose texture, mineralogy, or chemical composition has been altered without melting it.

Chemistry
1 answer:
AURORKA [14]3 years ago
6 0

Answer:

I believe it would be C or B

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at a certain pressure the density of superficial carbon dioxide is 0.469. what is the mass of a 25.0 mL sample of supercritical
Murrr4er [49]

Answer:

\large \boxed{\text{11.7 g}}

Explanation:

\text{Mass} = \text{25.0 mL} \times \dfrac{\text{0.469 g}}{\text{1 mL}} = \textbf{11.7 g}\\\\\text{The mass of the carbon dioxide is $\large \boxed{\textbf{11.7 g}}$}

7 0
3 years ago
Why dose sand absorbe heat faster than the water at the beach? and how do you know?
TiliK225 [7]
The specific heat capacity of sand is much less than water because of which sands require less energy to cool down and similarly less energy to be heated... because of this it feels like sands absrob heat faster than water
6 0
3 years ago
Which statement describes the Arrhenius interpretation of acids and bases?
Alexeev081 [22]

Answer:

D. It is limited to situations that involve aqueous solutions or specific compounds.

Explanation:

An Arrhenius acid is a substance that increases the concentration of H3O or H+ when dissolved in water. An Arrhenius base is a substance that increases the concentration of OH- when dissolved in water. These definitions tell us that D is indeed limited to situations that involve aqueous solutions or specific compounds, as aqueous means something that's dissolved in water.

A is wrong because the Bronsted-Lowry interpretation has a wider range of applications. Bronsted-Lowry acids and bases don't even need to be aqueous, so it is not limited to just aqueous solutions. They include any substance that can donate or accept a H+.

B is wrong because A is wrong. A and B basically say the same thing, that the Arrhenius interpretation has a wider range of applications than the Bronsted-Lowry interpretation.

C is wrong because the definition of an Arrhenius base is any substance that increases the concentration of OH-, or hydroxide ions. C completely counters this statement.

Here's photo for proof incase you're doubtful of my answer & explanation. Please click the heart if it helped.

6 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%
Elan Coil [88]

Let's check Electronic configuration of N in ground state

\\ \sf\longmapsto 1s^22s^22p^3

  • In exited state

\\ \sf\longmapsto 1s^22s^22px^12py^12pz^2

  • 3 p orbitals

In hydrogen case

\\ \sf\longmapsto 1s^1

  • 1 s orbital

Hence Hybridization

\\ \sf\longmapsto s-p-p-p

\\ \sf\longmapsto sp^3

Structure is tetrahedral .

Spare way:-

  • Bond pairs==3=>Bonding electrons=6
  • Lone pair=1=>Anti bonding electrons=2

Hybridization

\\ \sf\longmapsto \dfrac{1}{2}[\sigma+\sigma *]

\\ \sf\longmapsto \dfrac{1}{2}[6+2]

\\ \sf\longmapsto \dfrac{1}{2}[8]

\\ \sf\longmapsto 4

  • sp3 Hybridization
  • Shape-Tetrahedral .

6 0
2 years ago
The reaction, 2 SO3(g) &lt;--&gt; 2 SO2(g) + O2(g) is endothermic. Predict what will happen if the tem­perature is increased.
baherus [9]

Explanation:

This reaction is in equilibrium and would hence obey lechatelier's principle. This principle states that whenever a system at equilibrium undergoes a change, it would react in way so as to annul that change.

Since it is an endothermic reaction, increasing the temperature would cause the reaction to shift towards the right.

This means that it favours product formation and more of the product would be formed.

8 0
3 years ago
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