Answer:
2.15 mg of uranium-238 decays
Explanation:
For decay of radioactive nuclide-

where N is amount of radioactive nuclide after t time,
is initial amount of radioactive nuclide and
is half life of radioactive nuclide
Here
,
and 
So,
so, N = 2.446 mg
mass of uranium-238 decays = (4.60-2.446) mg = 2.15 mg
Answer:
Make the question more clear for me
Explanation:
Answer:
It is referred to as the van't Hoff factor.
Explanation:
The van't Hoff factor is named after the Dutch chemist Jacobus Henricus van 't Hoff. It can also be defined as the ratio of the actual quantity of particles to the quantity of particles for no ionization.The fundamental assumption of the van't Hoff factor is that the substance is a nonelectrolyte.