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loris [4]
3 years ago
14

You must obey any special signs or instructions as you pass a construction zone.

Computers and Technology
2 answers:
jenyasd209 [6]3 years ago
7 0
A. because if not something bad could happen
valkas [14]3 years ago
5 0
That is easy it is a
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Anti-lock braking systems can significantly.... a. impede your braking stability. B. improve your braking stability. C. improve
Setler79 [48]
Here is the answer that would best complete the given statement above. Anti-lock braking systems can significantly improve your braking stability. The correct answer would be therefore, option B. Anti-lock braking systems is for safety purposes in order for to prevent <span>the wheels from </span>locking<span> up (ceasing rotation) and avoiding uncontrolled skidding. Hope this answer helps.</span>
7 0
4 years ago
Write a function DrivingCost() with input parameters drivenMiles, milesPerGallon, and dollarsPerGallon, that returns the dollar
posledela

Answer:

#include <iostream>

using namespace std;

double DrivingCost(int drivenMiles,double milesPerGallon,double dollarsPerGallon)

{

   double dollarsperMile=dollarsPerGallon/milesPerGallon;//calculating dollarsperMile.

   return dollarsperMile*drivenMiles;//returning thr driving cost..

}

int main() {

double ans;

int miles;

cout<<"Enter miles"<<endl;

cin>>miles;

ans=DrivingCost(miles,20.0,3.1599);

cout<<ans<<endl;

return 0;

}

Output:-

Enter miles

10

1.57995

Enter miles

50

7.89975

Enter miles

100

15.7995

Explanation:

In the function first I have calculated the dollars per mile and after that I have returned the product of dollarspermile and driven miles.This will give the cost of the Driving.

4 0
3 years ago
Calculate the data rate capacity for a 2400 baud signal where there are M=8 levels per symbol. a. 2400 bps b. 4800 bps c. 7200 b
zimovet [89]

Answer:

C. 7200 bps.

Explanation:

In networking, transmission lines or connectors and ports operates at a specific speed based on the port type and the cable or medium of transmission.

Baud rate is a concept in digital information technology that defines the rate of symbol per channel during transmission. The bit or data rate is the number of bits transfered in a link per second.

The relationship between baud rate and bit rate is;

Bit rate = baud rate x number of symbol bit level

To get the bit rate of a 2400 baud signal with symbol level = 8 = 2^3

Bit rate = 2400 x 3. = 7200 bps.

7 0
3 years ago
The factorial of n is equal to ______.
alexdok [17]

Answer:

n! = n*(n-1)*(n-2)*(n-3)* ... *2*1

Explanation:

The factorial operator is simply a mathematical expression of the product of a stated integer and all integers below that number down to 1.  Consider these following examples:

4! = 4 * 3 * 2 * 1

4! = 12 * 2 * 1

4! = 24

6! = 6 * 5 * 4 * 3 * 2 * 1

6! = 30 * 4 * 3 * 2 * 1

6! = 120 * 3 * 2 * 1

6! = 360 * 2 * 1

6! = 720

So, the factorial of n would follow the same as such:

n! = n * (n-1) * (n-2) * ... * 2 * 1

Cheers.

5 0
3 years ago
Hello, my first time being here and I'm returning back from college and I'm now studying Java in college but I was stuck doing t
KengaRu [80]

Answer:

import java.time.LocalDate;

class TestWedding {

 public static void main(String[] args) {

   Person man1 = new Person("John", "Doe", LocalDate.parse("1990-05-23"));

   Person woman1 = new Person("Jane", "Something", LocalDate.parse("1995-07-03"));

   Person man2 = new Person("David", "Johnson", LocalDate.parse("1991-04-13"));

   Person woman2 = new Person("Sue", "Mi", LocalDate.parse("1997-12-01"));

   Couple cpl1 = new Couple(man1, woman1);

   Couple cpl2 = new Couple(man2, woman2);

   Wedding wed1 = new Wedding(cpl1, "Las Vegas", LocalDate.parse("2020-09-12"));

   Wedding wed2 = new Wedding(cpl2, "Hawaii", LocalDate.parse("2021-01-02"));  

   displayDetails(wed1, wed2);

 }

 public static void displayDetails(Wedding w1, Wedding w2) {

   System.out.println(w1.toString());

   System.out.println(w2.toString());

 }

}

---------------------------

class Couple {

 private Person person1;

 private Person person2;

 public Couple(Person p1, Person p2) {

   person1 = p1;

   person2 = p2;

 }

 public String toString() {

   return person1.toString() + " and " + person2.toString();

 }

}

----------------------------

import java.time.LocalDate;

import java.time.format.DateTimeFormatter;

class Person {

 private String firstName;

 private String lastName;

 private LocalDate birthDate;

 public Person(String first, String last, LocalDate bdate) {

   firstName = first;

   lastName = last;

   birthDate = bdate;

 }

 public String getFirstName() {

   return firstName;

 }

 public String toString() {

   DateTimeFormatter formatter = DateTimeFormatter.ofPattern("LLLL dd, yyyy");

   return String.format("%s %s born %s", this.firstName, this.lastName, birthDate.format(formatter));

 }

}

------------------------------------

import java.time.LocalDate;

import java.time.format.DateTimeFormatter;

class Wedding {

 private Couple couple;

 private String location;

 private LocalDate weddingDate;

 public Wedding(Couple c, String loc, LocalDate wDate) {

   couple = c;

   location = loc;

   weddingDate = wDate;

 }

 public String getLocation() {

       return this.location;

 }

 public String toString() {

   DateTimeFormatter formatter = DateTimeFormatter.ofPattern("LLLL dd, yyyy");

   return  

     couple.toString() +  

     " are getting married in " + location + " on "+

     weddingDate.format(formatter);

 }

}

Explanation:

I used overrides of toString to let each object print its own details. That's why this solution doesn't really require any getters. I implemented some to show how it's done, but you'll have to complete it. The solution shows how to think in an OO way; ie., let every class take care of its own stuff.

6 0
3 years ago
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