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wariber [46]
3 years ago
10

Which scientist proposed the model of an atom as a solid sphere?

Chemistry
1 answer:
MaRussiya [10]3 years ago
6 0

Answer:

John Dalton

Explanation:

The Solid Sphere Model was the first atomic model and was developed by John Dalton in the early 19th century. He hypothesized that an atom is a solid sphere that could not be divided into smaller particles.

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Hydrogen bond is an example for? (PLEASE HELP!)
zlopas [31]

Answer:

b)

Explanation:

hydrogen bond is a form of dipole-dipole interaction but with more unique properties

3 0
3 years ago
The solubility of CO2 in water is 0.161 g/100 mL at 20oC and a partial pressure of CO2 of 760 mmHg. What partial pressure of CO2
Schach [20]

<u>Answer:</u> The partial pressure of carbon dioxide having solubility 0.886g/100mL is 4182.4 mmHg

<u>Explanation:</u>

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

The equation given by Henry's law is:

C_{CO_2}=K_H\times p_{CO_2}       ......(1)

where,

C_{CO_2 = solubility of carbon dioxide in water = 0.161 g/100 mL

K_H = Henry's constant = ?

p_{CO_2} = partial pressure of carbon dioxide = 760 mmHg

Putting values in equation 1, we get:

760mmHg=K_H\times 0.161g/100mL\\\\K_H=\frac{760mmHg}{0.161g/100mL}=4720.5g.mmHg/100mL

Now, calculating the pressure of carbon dioxide using equation 1, we get:

C_{CO_2 = solubility of carbon dioxide in water = 0.886 g/100 mL

K_H = Henry's constant = 4720.5 g.mmHg/100 mL

p_{CO_2} = partial pressure of carbon dioxide = ?

Putting values in equation 1, we get:

p_{CO_2}=4720.5g.mmHg/100mL\times 0.886g/100mL=4182.4mmHg

Hence, the partial pressure of carbon dioxide having solubility 0.886g/100mL is 4182.4 mmHg

4 0
3 years ago
Are you my mother? Please answer me...
erastovalidia [21]
No sorry because i'm only 12 years old so no

7 0
3 years ago
Read 2 more answers
Many grams of aluminum are required to produce 3.5 moles Al2O3 in the presence of excess O2?
Aleks [24]
The  grams  of aluminum  that are required   to produce  3.5  moles of AlO3  in  presence of excess O2   is calculated as  below

write  the  equation for reaction
4 Al + 3O2 =2 Al2O3

by use of mole  ratio between  Al  to  Al2O3   which  is  4 :2  the moles of  Al 
=3.5 x4/2 = 7  moles

mass of Al  =  moles /   x molar mass

= 7 moles  x27 g/mol  =189  grams

4 0
3 years ago
For a laboratory investigation some students put a strip of shiny metal into a beaker of blue solution and then stored the beake
KatRina [158]

Answer:

b

Explanation:

8 0
3 years ago
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