Answer:
1.iron lead zinc
2)calcium barium magnesium
a. Using the Clausius-Clapeyron equation
ln P1/P2 = (-Hvap / R) (1/T1 - 1/T2)
P1 = 197 mm Hg
P2 = 448 mm Hg
T1 = 23 C = 296 K
T2 = 45 C = 318 K
R = 8.314 J/mol-K
Solving for Hvap
Hvap = <span>29225.43 J/mol
b. For normal boiling point
</span>P1 = 197 mm Hg
P2 = 760 mm Hg (normal pressure)
T1 = 23 C = 296 K
T2 = ?
R = 8.314 J/mol-K
Hvap = 29225.43 J/mol
ln P1/P2 = (-Hvap / R) (1/T1 - 1/T2)
Use the equation to solve for T2
A because cation is positive and anion is negative evening it out at constant.
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Answer:
155 A
Explanation:
Given data
- Transported charge (Q): 93.0 Coulomb
- Elapsed time (t): 601 ms = 0.601 seconds
We can determine the magnitude of the electric current (I) using the following expression.
I = Q / t
I = 93.0 C / 0.601 s
I = 155 C/s
I = 155 A
The magnitude of the electric current is 155 Ampere.
