Answer:
this is for nwea..
Step-by-step explanation:
To make the sure the results did not happen by chance, the coach can ensure that the protein bars are the only difference between the two groups. For example, he can make sure that both groups are drinking the same amounts of water and getting in the same amount of practice; that way, he will be able to determine that one group is performing better due to the protein bars only. Also, the coach can repeat this experiment multiple times to make sure that the results weren't a random, one-time thing.
Answer:
Total area of figure = [3x² + 7x + 6] feet²
Step-by-step explanation:
By dividing both rectangle by vertical line;
Given:
Length of big rectangle = (x + 3) feet
Width of big rectangle = (x + 2) feet
Length of small rectangle = 2x feet
Width of small rectangle = (x + 1) feet
Find:
Total area of figure
Computation:
Area of rectangle = Length x width
Total area of figure = Area of big rectangle + Area of small rectangle
Total area of figure = [(x + 3)(x + 2)] + [(2x)(x + 1)]
Total area of figure = [x²+ 2x + 3x + 6] + [2x² + 2x]
Total area of figure = [3x² + 7x + 6] feet²
Answer:
a) the probability that the minimum of the three is between 75 and 90 is 0.00072
b) the probability that the second smallest of the three is between 75 and 90 is 0.396
Step-by-step explanation:
Given that;
fx(x) = { 1/5 ; 50 < x < 100
0, otherwise}
Fx(x) = { x-50 / 50 ; 50 < x < 100
1 ; x > 100
a)
n = 3
F(1) (x) = nf(x) ( 1-F(x)^n-1
= 3 × 1/50 ( 1 - ((x-50)/50)²
= 3/50 (( 100 - x)/50)²
=3/50³ ( 100 - x)²
Therefore P ( 75 < (x) < 90) = ⁹⁰∫₇₅ 3/50³ ( 100 - x)² dx
= 3/50³ [ -2 (100 - x ]₇₅⁹⁰
= (3 ( -20 + 50)) / 50₃
= 9 / 12500 = 0.00072
b)
f(k) (x) = nf(x) ( ⁿ⁻¹_k₋ ₁) ( F(x) )^k-1 ; ( 1 - F(x) )^n-k
Now for n = 3, k = 2
f(2) (x) = 3f(x) × 2 × (x-50 / 50) ( 1 - (x-50 / 50))
= 6 × 1/50 × ( x-50 / 50) ( 100-x / 50)
= 6/50³ ( 150x - x² - 5000 )
therefore
P( 75 < x2 < 90 ) = 6/50³ ⁹⁰∫₇₅ ( 150x - x² - 5000 ) dx
= 99 / 250 = 0.396
Answer:
62 units
Step-by-step explanation:
The absolute value of a number A is the positive distance between 0 and the number A (you can think this distance as the distance measured with a ruler from 0 to the number). For example:
|-2|=2 , |25|=25, |-3|=3, |-25.3|=25.3
Note that the absolte value is always positive.
The distance between two numbers P,Q in the real line is the absolute value of the difference between the two points:
Hence, the distnce between P=-50 and Q=12 is equal to
