Answer:
<h2>The angular velocity just after collision is given as</h2><h2>
</h2><h2>At the time of collision the hinge point will exert net external force on it so linear momentum is not conserved</h2>
Explanation:
As per given figure we know that there is no external torque about hinge point on the system of given mass
So here we will have
now we can say
so we will have
Linear momentum of the system is not conserved because at the time of collision the hinge point will exert net external force on the system of mass
So we can use angular momentum conservation about the hinge point
Yes I believe it would I think the answer is D
Density is calculated as mass per unit volume. In this case, since the material has a mass of 47 grams and we have the volume of 15 cm^3, we can simply divide the values:
Density = 47 grams / 15 cm^3 = 3.1 g/cm^3
Therefore, the material has a density of 3.1 g/cm^3
I haven't, but I'm sure @Porshia has!
Given data
ball throws upwards at an angle 60°
Horizontal component (Vh) = 12.5 m/s,
Vertical component (Vv) = 21.7 m/s ,
The magnitude of throw/resultant velocity (V) = ?
The resultant velocity /the velocity with which ball is throws is determined by the following equation
V = √[(Vh)² + (Vv)²]
= √[(12.5)² + (21.7)²]
= 25.04 m/s
<em> The resultant velocity or the velocity with which the ball is thrown is 25 m/s</em>
