Given :
Capacity of capacitor is, 
.
To Find :
At what voltage can a 10 μF capacitor be energized to 0.45 J.
Solution :
We know, energy in capacitor is given by :
So,
Therefore, voltage required is 
.
Answer:
1.65 atm
Explanation:
Applying,
PV = nRT....................... Equation 1
Where P = Pressure, V = Volume, n = number of moles, R = malar gas constant, T = Temperature.
Make P the subject of the equation
P = nRT/V..................... Equation 2
From the question,
Given: n = 3.27 moles, V = 50.0 L, T = 35 °C = (273+35) = 308K
Constant: R = 0.082L.atm/K.mol
Substitute these values into equation 2
P = 3.27(0.082)(308)/(50)
P = 1.65 atm
More friction because it's smooth
Momentum = mass x velocity
So both mass and velocity affect an object's momentum.
Explanation:
Here,
Given,
Mass(m)=40 kg
Gram=9.8m/s
Now,
Weight=m x g
or, weight= 40x9.8
=392.0
Hope you have understood
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