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Bess [88]
2 years ago
11

Clouds absorb outgoing radiation emitted by earth and reradiate a portion of it back to the surface during _____.

Physics
1 answer:
GarryVolchara [31]2 years ago
4 0
I would say the correct answer is nighttime. The clouds in the atmosphere would absorb the radiation that is emitted by the Earth and at at night 30% of these would be radiated back to the Earth's surface. Hope this answers the question. <span />
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Please help me with this and if I have good answer u will be marked as brilliant !!!!
AysviL [449]
Number one- numbers of items sold. Number two- Thursday and Friday. Number three- 1,200. Number four-150
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3 years ago
Understanding that if we say something unkind to someone else his or her
OlgaM077 [116]

Answer: Moral

Explanation:

6 0
3 years ago
The drag force on a falling coffee filter can be modeled as a linear function with respect to velocity, F⃗ D =−bv, where b is a
nordsb [41]

Newton's second law and graphical analysis allow us to find the correct answer for the measure of the constant b is:

    D) Stack several filters to change the mass measure the acceleration of the system.

Newton's second law establishes a relationship between the net force, the mass and the acceleration of the bodies.  

         ∑ F = m a

Where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.

They indicate that the drag force on the filters is

         F = - b v

Where b is a positive constant that depends on the shape and area of ​​the filter and v is the speed of the filter.

Let's write Newton's second law.

         W - fr  = ma

         W -bv  = ma

         

In the experiment the students indicate that they can measure the position, velocity and acceleration of the body.

Based on the above, if we place several filter weights and measure their speed and acceleration in each case, we can make a graph of velocity versus acceleration, we can take the value of the constant b from the slope.

Let's analyze the different answers:

A) False. The constant b depends on the shape of the filter therefore it must be kept constant.

B) False. The constant depends on the area, so it must be kept constant.

C) May be. In this case, since we have the terminal velocity, the acceleration is zero, Newton's second law remains.

                    B v - W = 0

                    b = \frac{W}{v}  

The problem with the method is the difficulty of measuring the compression terminal velocity.

D) True. According to the discussion of the velocity versus acceleration. graph, the constant b is equal to the slope of the graph.

E) May be. The problem with this method is finding a reliable value for the terminal velocity.

In conclusion, using Newton's second law and graphical analysis we can find the correct answer for the measure of the constant b is:

 D) Stack several filters to change the mass measure the acceleration of the system.

Learn more here:  brainly.com/question/2441565

6 0
2 years ago
A radio telescope has a circular collecting dish of diameter 5.0 m. It is used to observe two distant
Likurg_2 [28]
Skskdidododododoorrororo
3 0
2 years ago
A ball is kicked at an angle of 35° with the ground.a) What should be the initial velocity of the ball so that it hits a target
stiks02 [169]

Answer:

a.18.5 m/s

b.1.98 s

Explanation:

We are given that

\theta=35^{\circ}

a.Let v_0 be the initial velocity of the ball.

Distance,x=30 m

Height,h=1.8 m

v_x=v_0cos\theta=v_0cos35

v_y=v_0sin\theta=v_0sin35

x=v_0cos\theta\times t=v_0cos35\times t

t=\frac{30}{v_0cos35}

h=v_yt-\frac{1}{2}gt^2

Substitute the values

1.8=v_0sin35\frac{30}{v_0cos35}-\frac{1}{2}(9.8)(\frac{30}{v_0cso35})^2

1.8=30tan35-\frac{6574.6}{v^2_0}

\frac{6574.6}{v^2_0}=21-1.8=19.2

v^2_0=\frac{6574.6}{19.2}

v_0=\sqrt{\frac{6574.6}{19.2}}=18.5 m/s

Initial velocity of the ball=18.5 m/s

b.Substitute the value then we get

t=\frac{30}{18.5cos35}

t=1.98 s

Hence, the time for the ball to reach the target=1.98 s

7 0
3 years ago
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