Gold is a chemical element with symbol Au (from Latin: aurum) and atomic number 79, making it one of the higher atomic number elements that occur naturally. In its purest form, it is a bright, slightly reddish yellow, dense, soft, malleable, and ductile metal.
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<u>Explanation:</u>
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Explanation:
Atomic number of magnesium is 12 and its electronic distribution is 2, 8, 2. On the other hand, atomic number of iodine is 53 and its electronic configuration is
.
Hence, there are 7 valence electrons in an iodine atom and there are 2 valence electrons in a magnesium atom.
So, one atom of iodine requires one electron from a donor atom to complete its octet. But one magnesium atom contains two valence electrons.
Therefore, one magnesium atom will combine with two iodine atoms to result in the formation of magnesium iodide as follows.

Therefore, an ionic bond will be formed when magnesium reacts with iodine to make magnesium iodide.
Answer:
Boron
Explanation:
You can find this by looking at the number of protons in Boron, 5.
Then calculate how many electrons you are given, in this case the 2 core plus the 3 valence equal 5 total electrons
Neutral elements have the same number of protons and electrons, so your answer would be the element with 5 electrons, Boron.
You can also know this by using electron configuration. Since you kow there are 5 electrons then you can use EC to find out where your element is. In this case it is: 1s2 2s2 2p1