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solong [7]
3 years ago
8

Which organism in a food web would be best described as a recycler?

Chemistry
1 answer:
Anika [276]3 years ago
7 0

C,

takes dead things, makes them into other things

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Question 1
Nesterboy [21]
P waves are faster S wave are slower P waves can pass through both solids and liquids S waves bounce of solids
3 0
3 years ago
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A gas has an initial volume of 455 mL at 105ºC and a final volume of 235 mL. What is its final temperature in Celsius degrees?
Oksana_A [137]
Hello!

To solve this problem we're going to use the Charles' Law. This Law describes the relationship between Volume and Temperature in an ideal gas. Applying this law we have the following equation:

\frac{V1}{T1} = \frac{V2}{T2} \\  \\ T2= \frac{V2*T1}{V1}=  \frac{235 mL * 105  ^{\circ}C }{455 mL}=54,23 ^{\circ}C

So, the final temperature is 54,23 °C

Have a nice day!
5 0
4 years ago
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What is the daughter nucleus (nuclide) produced when 64 Cu Cu64 undergoes beta decay by emitting an electron? Replace each quest
kenny6666 [7]

<u>Answer:</u> The daughter nuclide formed by the beta decay of given isotope is _{30}^{64}\textrm{Zn}

<u>Explanation:</u>

Beta decay is defined as the process in which beta particle is emitted. In this process, a neutron gets converted to a proton and an electron.

The released beta particle is also known as electron.

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

We are given:

Parent isotope = _{29}^{64}\textrm{Cu}

The chemical equation for the beta decay process of _{29}^{64}\textrm{Cu} follows:

_{29}^{64}\textrm{Cu}\rightarrow _{30}^{64}\textrm{Zn}+_{-1}^0\beta

Hence, the daughter nuclide formed by the beta decay of given isotope is _{30}^{64}\textrm{Zn}

4 0
4 years ago
Convert the composition of the following alloy from atom percent to weight percent (a) 44.9 at% of silver, (b) 46.3 at% of gold,
vesna_86 [32]

Answer:

Mass percentage of gold : 33.35%

Mass percentage of silver: 62.80%

Mass percentage of copper : 3.85%

Explanation:

N=n\times N_A

Where : N = Number of atoms

n = moles

N_A=6.022\times 10^{23} = Avogadro number

Let the total atoms present in the alloy be 100.

Atom percentage of silver = 44.9%

Atoms of of silver = 44.9% of 100 atoms = 44.9

Atomic weight of silver = 107.87 g/mol

Mass of 44.9 silver atoms = 107.87 g/mol ×  44.9 = 4,843.363 g/mol

Atom percentage of gold= 46.3%

Atoms of of gold = 46.3% of 100 atoms = 46.3

Atomic weight of gold = 196.97 g/mol

Mass of 44.9 gold atoms = 196.97 g/mol × 46.3 = 9,119.711 g/mol

Atom percentage of copper = 8.8 %

Atoms of of copper = 8.8% of 100 atoms = 8.8

Atomic weight of copper = 63.55 g/mol

Mass of 44.9 copper atoms = 63.55 g/mol ×  8.8 = 559.24 g/mol

Total mass of an alloy :4,843.363 g/mol + 9,119.711 g/mol +  559.24 g/mol

Mass percentage of gold :

\frac{4,843.363 g/mol}{4,843.363 g/mol + 9,119.711 g/mol +  559.24 g/mol}\times 100=33.35 \%

Mass percentage of silver:

\frac{9,119.711 g/mol}{4,843.363 g/mol + 9,119.711 g/mol +  559.24 g/mol}\times 100=62.80\%

Mass percentage of copper :

\frac{559.24 g/mol}{4,843.363 g/mol + 9,119.711 g/mol +  559.24 g/mol}\times 100=3.85\%

7 0
3 years ago
Species developed harder shelled eggs to raise them on land, this is to adapt to the changes in the enviorment during the Cenozo
mario62 [17]
False would be the answer
6 0
3 years ago
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