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Firlakuza [10]
4 years ago
8

What intermolecular force involves non polar molecules

Chemistry
1 answer:
Zolol [24]4 years ago
7 0

Dispersion forces are the only type of intermolecular force operating between non-polar molecules, for example, dispersion forces operate between hydrogen (H2) molecules, chlorine (Cl2) molecules, carbon dioxide (CO2) molecules, nitrogen tetroxide (N2O4) molecules and methane (CH4) molecules.

www.ausetute.com.au/intermof.html


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I believe that would be methane! I hope this helps you!

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An alcohol with molecular formula CnH2n+1OH has a chiral carbon atom but does not react with
Nady [450]
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Calculate the mass of forsterite that contains a million oxygen atoms. Be sure your answer has a unit symbol if necessary, and r
Gekata [30.6K]

Answer:

2.33×10¯¹⁶ g of forsterite

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ atoms. This equally means that 1 mole of forsterite (Mg2SiO4) contains 6.02×10²³ atoms.

1 mole of forsterite (Mg2SiO4) = (24×2) + 28 + (16×4)

= 48 + 28 + 64

= 140 g

Finally, we shall determine the mass of forsterite that contains a million oxygen atoms.

140 g of forsterite (Mg2SiO4) contains 6.02×10²³ atoms.

Therefore, Xg of forsterite (Mg2SiO4) will contain 1×10⁶ atoms of oxygen i.e

Xg of forsterite (Mg2SiO4) =

(140 × 1×10⁶) /6.02×10²³

= 2.33×10¯¹⁶ g

Therefore, 2.33×10¯¹⁶ g of forsterite contains a million oxygen atoms..

5 0
3 years ago
What is the mass of 2.50 × 1025 molecules of sugar (c12h22o11)?
allochka39001 [22]
To determine the mass of the sugar molecules given, we  need to convert the given value into moles by using the a constant. <span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. Then, by using the molar mass of sugar, we can convert from moles to grams. Molar mass of sugar is 342.3 g/mol. We do as follows:

</span><span>2.50 × 10^25 molecules of sugar ( 1 mol / 6.022x10^23 g ) ( 342.3 g / 1 mol) = 14210.40 grams of sugar present</span>

3 0
4 years ago
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