Answer:
1 L = 1000 cm^3
1 m^3 = 1000 L = 10^6 cm^3
1 m^3 = 10^6 g = 10^3 kg density of water
M = Density * Volume
V = 2 * 4 * 5 = 40 m^3
M = 10^3 kg / m^3 * 40 m^3 = 4.0 * 10^4 kg
Is the weighted average mass of an atom of an element based on the relative of natural abundance of that isoptopes of elements.
Answer:
Explanation:
The displacement current is given by the expression;
where
Answer:
The answer is <em>neither</em>.
Explanation:
The reason to why the <em>answer is neither</em> is because in order to jump start a vehicle you must:
- <em>Park the booster vehicle close to the hood of the vehicle that needs to be boosted.</em>
- <em>Set the parking brakes on both vehicles.</em>
- <em>Open the hoods of both vehicles to access the starting battery. On some vehicles this also in the trunk.</em>
- <em>Connect the clamp at the other end of the positive jumper cable (red) to the positive terminal on the battery or the jump-starting terminal.</em>
- <em>Connect the clamp at the other end of the positive jumper cable (red) to the positive terminal on the booster battery.</em>
- <em>Connect the clamp of the negative jumper cable (black) to the negative terminal on the booster battery.</em>
- <em>Connect the clamp at the other end of the negative jumper cable (black) to a piece of exposed metal part of the dead vehicle's engine and ensure that it is far away from any fuel or the battery.</em>
- <em>Run the engine of the booster vehicle for about 5 minutes.</em>
- <em>Now try to start the dead vehicle.</em>
- <em>If the vehicle does not start, check the connections of the different cables. If the engine does not start, then it should either be charged or replaced.</em>
- <em>Once the dead vehicle's engine has started, allow both vehicles to run for about 5 minutes.</em>
- <em>Then disconnect the negative cable from the vehicle and then from the booster battery.</em>
- <em>Then disconnect the positive cable from the vehicle and from the booster battery. </em>
Answer:
*he force to climb a plane inlcinado with constant velicad is equal to the cosine of the weight of the body
*he force to climb a plane inlcinado with constant velicad is equal to the cosine of the weight of the body
Explanation:
When a car is going up an inclined plane with constant speed, we can solve the problem using the translational equilibrium equation
Let's locate one axis parallel to the plane and the other perpendicular
F - W x = 0
F = W cos tea
therefore wes ee that the force to climb a plane inlcinado with constant velicad is equal to the cosine of the weight of the body
Work is defined by
W = F. l
in this case the force and displacement are constant
W = F L
where L is the length of the plane
W = mgL cos tes
we see that the work is equal to the cosine of the force times the distance on the plane