1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nalin [4]
3 years ago
5

ILL GIVE BRAINLIEST Combine like terms. 4x – 7y + 2x – 4 = [ ? ]x + [ ]y + [ ]

Mathematics
2 answers:
maxonik [38]3 years ago
7 0

Answer:

[6x] + [-7y] + [-4]

Step-by-step explanation:

There are only two like terms in this expression "4x" and "2x." Since they are like terms we can combine them by adding the coefficients and keeping the variable attached. Therefore we can combine 4x and 2x into 6x. Since there are no more like terms, this expression can be simplified to 6x - 7y - 4.

kvasek [131]3 years ago
5 0
Answer:

6x - 7y - 4

Step-by-step explanation:

4x - 7y + 2x - 4

Combine like terms (by either subtracting or adding a number with the same variable)

4x + 2x = 6x

Thus, only one like term so the final answer is

6x - 7y - 4
You might be interested in
Estimate the quotient of 1246 divided by 4
VladimirAG [237]

Answer:

623/2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
(1) a) 5270 cl= ? dal
Ivanshal [37]

Answer:

Check below

Step-by-step explanation:

1) These metric volume units can be easily converted by dividing or multiplying by 10 and its multiple. Like this: each step up on the ladder multiply by 10. Each step down divide by 10

a)5270 \:cl=527\:dl\\b)kl=5.3 \times 10=530 hl\\c)58000ml=5.8 dal =(\frac{58000}{10000})\\d)0.39 dal=3.9 l\\e)7.8 dal=780 dl\\f)57.2 ml=5.72 cl.

2) When it comes to area, the "ladder scheme" remains valid but now we'll multiply or divide by

10^3

Bear in mind these useful relations:

1litre =\frac{1}{10^3}m^{3}

1 cm^{3} =1 ml

a) 3.7 l=3700 cm^{3}\\b)29.6 dm^{3}\\29.6 dm^{3} \rightarrow 29.6\times10^{3} cm^3=29.6\times10^{3} ml = 29.6\times10^{2} cl \:or\:2960 cl\\c)8.1l=8100 cm^{3}\\d)5l=\frac{5}{10^{-3}} m^{3}\\e)5.2 cl=52ml=52 cm^{3}=52\times10^{3}=52000 \:mm^{3}\\f)375 ml=375 cm^{3}\\g) 1300 cm^{3}=1300 ml=13 dl\\h) 8.6 ml= 8.6 cm^{3}\times\: 10^{3}=8600 mm^{3}\\i) 51.8\times 10^{11} l \rightarrow 51.8\times 10^{-11}km^{3}

6 0
3 years ago
Donte is making a pizza. The round pizza pan has a 18 inch diameter. What is the area of the Pizza crust will need to fill up th
Fittoniya [83]
A = pi(r)^2
diameter is 18in, so radius is 9in
= pi(9)^2
A = 254.469 (round is needed)
8 0
4 years ago
Write an explicit formula for an, the nth term of the sequence 27, 21, 15, ….
liq [111]

Answer:

nth=a+(n+1)d

Step-by-step explanation:

8 0
3 years ago
What and which at time are the maximum and minimum speeds in this function?
Svetach [21]

Answer:

the maximum is 12000 and the minimum is 0

Step-by-step explanation:

sorry if this doesn't answer your question

4 0
3 years ago
Read 2 more answers
Other questions:
  • Larry rolls 2 fair dice and adds the results from each.
    7·1 answer
  • Miguel napped for 2 2/5 hours. Danalya napped too. Combined they napped for 3 3/4 hours
    15·2 answers
  • 2. The line y = x is transformed into y = 5x. Determine if each statement
    10·1 answer
  • Write an algebraic expression that is the quotient of a variable term and a constant.
    11·1 answer
  • .Ileana is going to plant 12 small plants around the edge of a circular garden that is 10 feet in diameter. If she spaces the pl
    14·2 answers
  • A gardener measures the heights of 2 plants at the end of every week. The function y=3x+8.5 of plant A in centimeters at the end
    13·1 answer
  • Can someone help me do this? im really confused if you can send it to my insta candy.lishious
    15·1 answer
  • Micaela and Chelsea each improved their yards by planting rose bushes and ivy. They bought their supplies
    10·2 answers
  • What is the slope of line a? 48 POINTS
    10·2 answers
  • What is the product of 4(8x + 5).
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!