Answer:
T'=92.70°C
Explanation:
To find the temperature of the gas you use the equation for ideal gases:
V: volume = 3000cm^3 = 3L
P: pressure = 1250mmHg; 1 mmHg = 0.001315 atm
n: number of moles
R: ideal gas constant = 0.082 atm.L/mol.K
T: temperature = 27°C = 300.15K
For the given values you firs calculate the number n of moles:
this values of moles must conserve when the other parameter change. Hence, you have V'=2L and P'=3atm. The new temperature is given by:
hence, T'=92.70°C
Answer:
<em>The velocity of the carts after the event is 1 m/s</em>
Explanation:
<u>Law Of Conservation Of Linear Momentum </u>
The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is
P=mv.
If we have a system of bodies, then the total momentum is the sum of the individual momentums:
If a collision occurs and the velocities change to v', the final momentum is:
Since the total momentum is conserved, then:
P = P'
In a system of two masses, the equation simplifies to:
If both masses stick together after the collision at a common speed v', then:
The common velocity after this situation is:
The m1=2 kg cart is moving to the right at v1=5 m/s. It collides with an m2= 8 kg cart at rest (v2=0). Knowing they stick together after the collision, the common speed is:
The velocity of the carts after the event is 1 m/s
a) The mass of the ship is
b) The ship has a larger momentum than the shell
Explanation:
a)
The momentum of an object is given by:
where
m is the mass of the object
v is its velocity
For the ship in this problem, we have
is the momentum
is the velocity
Solving for m, we find the mass of the ship:
b)
The momentum of the artillery shell is given by
where
m is its mass
v is its velocity
For the shell in this problem,
m = 1100 kg
v = 1200 m/s
Substituting,
So, we see that the ship has a larger momentum.
Learn more about momentum:
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