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nikdorinn [45]
3 years ago
10

What mathematical formula correctly expresses the relationship between force, mass and acceleration? A. m = F + a B. F = m / a C

. a = mF D. F = ma
Physics
1 answer:
IRINA_888 [86]3 years ago
3 0

D. F=ma

F is for force, and that equals two things, M for mass and A for acceleration. When mass is accelerated, it gives you force. Force equals multiplying mass and its acceleration.

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Which amplitude of the following longitudinal waves has the greatest energy?
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Which amplitude of the following longitudinal waves has the greatest energy?

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6 0
3 years ago
A spring of negligible mass has force constant of 1600 Newtons per meter. (a) How far must the spring be compressed for 3.20 Jou
frez [133]

Answer:

a) x=63.0 x10^{-3} m or 6.3cm

b) x=116.0 x10^{-3} m or 11.6cm

Explanation:

a).

The elastic potential energy is modeling by equation :

U1=\frac{1}{2}*k*x^{2} \\K=1600 \frac{N}{m}\\ U=3.2J\\m=1.2kg\\x^{2}=\frac{2*U}{k}\\x=\sqrt{\frac{2*3.2J}{1600 \frac{N}{m}}} \\x=\sqrt{4x10^{-3} m^{2}}\\ x=0.06324m

b).

The work energy theorem explain which work is done in this case. the motion began from the rest so K1=K2 equal zero, Ug1 is no yet done and U2is also zero because is the potential energy

Ug=K2\\mgy=\frac{1}{2}*k*x^{2} \\but \\y=h+x=0.80m+x\\m*g*(0.80m+x)=\frac{1}{2}*k*x^{2}

Solving for x

2*(m*g(h+x))=k*x^{2} \\k*x^{2}-(2*m*g*x)-(2*m*g*h)=0\\1600x^{2} -2*1.2kg*9.8\frac{m}{s^{2}}*x-2*1.2kg*0.80m=0\\1600x^{2} -23.52x-18.816m=0

x=-\frac{b+/-\sqrt{b^{2}-4*a*c } }{2*a} \\x=-\frac{-23.52+/-\sqrt{-23.52^{2}-4*1600*-18.816 } }{2*a} \\x=11.79 +/- 173.9\\x1=-0.10 m\\x2=0.116

The negative is discard so

x=0.116m

7 0
3 years ago
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