Answer:
The acceleration of the player is - 4.9 m/s²
Explanation:
The given is:
1. The mass of the player is 55 kg
2. His initial speed is 4.6 m/s
3. The coefficient of the kinetic fraction between the player and the
ground is 0.50
We need to find the player acceleration
According to Newton's Law
→ ∑ forces in direction of motion = mass × acceleration
There is only the friction force opposite to the motion
→ Friction force = μR
where μ is the coefficient of friction and R is the normal reaction
→ The normal reaction R = mg
where m is the mass and g is the acceleration of gravity
→ m = 55 kg , g = 9.8 m/s²
→ R = 55 × 9.8 = 539 N
→ ∑ F = - μR
→ - μR = m × a
→ μ = 0.5 , R = 539 N , m = 55
→ -(0.5)(539) = 55 × a
→ - 269.5 = 55 a
Divide both sides by 55
→ a = - 4.9 m/s²
The acceleration of the player is - 4.9 m/s²
Learn more:
You can learn more about Newton's law in brainly.com/question/11911194
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It should be at the very top since it has more space to fall which gives it more potential energy
Answer:
-13.7m/s
Explanation:
If the car has a mass of 1400kg with a speed of +13.7m/s -> hits [email protected] rest and bounces with an elastic collision:
fm = -fm
Therefore, the speed the car will possess will be at a negative state.
= -13.7m/s
Answer:
Both waves are mechanical waves
Answer:
(c) 3 m/s;
Explanation:
Moment of inertia of the fish eels about its long body as axis
= 1/2 m R ² where m is mass of its body and R is radius of transverse cross section of body .
= 1/2 x m x (5 x 10⁻² )²
I = 12.5 m x 10⁻⁴ kg m²
angular velocity of the eel
ω = 2 π n where n is revolution per second
=2 π n
= 2 π x 14
= 28π
Rotational kinetic energy
= 1/2 I ω²
= .5 x 12.5 m x 10⁻⁴ x(28π)²
= 4.8312m J
To match this kinetic energy let eel requires to have linear velocity of V
1 / 2 m V² = 4.8312m
V = 3.10
or 3 m /s .
