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Otrada [13]
3 years ago
10

Calculate the number of moles of solute present in 55.0 mg of an aqueous solution that is 1.45 m NaCl. Assume that for dilute aq

ueous solutions, the mass of the solvent is the mass of solution.
Chemistry
1 answer:
Aloiza [94]3 years ago
8 0

Answer:

0.00007975 mole

Explanation:

Number of moles can be calculated as; mass of solute/volume of solvent or concentration of solution x volume of that solution.

In this case:

Concentration of solution = 1.45 M

Mass of solvent (water in this case) = 55.0 mg

55.0 mg of water is equivalent to 0.55 ml of water.

Therefore, volume of solution = 0.055 ml

Hence, number of moles of solute = molarity x volume

                                                           1.45 x 0.000055 = 0.00007975 mole

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Answer:

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Explanation:

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Design and implement a program (name it SumValue) that reads three integers (say X, Y, and Z) and prints out their values on sep
rjkz [21]

Answer:

class sum (

public static void sumofvalue (int m, int n, int p)

{

System.out.println(m);

System.out.println(n);

System.out.println(p);

int SumValue=m+n+p;

System.out.println("Average="+Sumvalue/3);

}

)

Public class XYZ

(

public static void main(String [] args)

{

sum ob=new sum();

int X=3;

int X=4;

int X=5;

ob.sumofvalue(X,Y,Z);

int X=7;

int X=8;

int X=10;

ob.sumofvalue(X,Y,Z);

}

)

Explanation:

The above program is made in Java, in which first we have printed value in a separate line. After that, the average value of those three values has been printed according to the question.

The processing of the program is given below in detail

* The first one class named 'sum' has been created which contains the function to print individual value and the average of those three values.

* In seconds main class named 'XYZ', the object of that the above class had been created which call the method of the above class to perform functions.

* In the main class values are assigned to variables X, Y, Z.

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Ivanshal [37]

Hey there,

Your answer would be

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Hope this helps,

<h2>- <em>Mr. Helpful</em></h2>

8 0
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stellarik [79]
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7 0
3 years ago
Read 2 more answers
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