Ask question

Ask question

All categories

3 years ago

12

If an atom has two electrons outside of its nucleus, what number of protons and neutrons must be contained in the nucleus to res

ult in a neutral atom? A. 2 protons, 2 neutrons B. 1 proton, 1 neutron C. 1 proton, 3 neutrons D. 4 protons, 4 neutrons

1 answer:

vichka [17]3 years ago

5 0

A

an element in a neutral state will have the same number of protons and electrons.

You might be interested in

A truck is traveling 20m/s accelerates 3 m/s^2 for 4 seconds how far did it travel while it was accelerating. Using guess method

stellarik [79]

<h3> $\huge\underline\bold\blue{ƛƝƧƜЄƦ}$ </h3><h3>Given</h3>

$\blue\star$ v = 20m\s

$\blue\star$ a = 3m\s^2

$\blue\star$ t = 4sec

Firstly we have to find u

$\star$ a = $\dfrac{v - u}{t}$

$\star$ 3m\s = $\dfrac{20 - u}{4}$

$\star$ 12m\s = 20 - u

$\star$ 20 - u = 12m\s

$\star$ - u = -8

$\star$ u = 8

Now we can easily find distance by using second equation of motion

$\red\star$ s = ut + 1\2 at^2

$\red\star$ s = 8(4) + 1\2(3)(16)

$\red\star$ s = 32 + 24

$\red\star$ s = 56

So distance is 56 m\s hope it helps

5 0

3 years ago

A motor develops 80 kW of power as it lifts a loaded elevator 20.5 m in 45 s. How much force does the motor exert? *

yuradex [85]

Answer:

F=1.3⋅105N

Explanation:

It's common knowledge.

7 0

3 years ago

A boy in a wheelchair (total mass 54.5 kg) has speed 1.40 m/s at the crest of a slope 2.10 m high and 12.4 m long. At the bottom

babymother [125]

Answer:

630.75 j

Explanation:

from the question we have the following

total mass (m) = 54.5 kg

initial speed (Vi) = 1.4 m/s

final speed (Vf) = 6.6 m/s

frictional force (FF) = 41 N

height of slope (h) = 2.1 m

length of slope (d) = 12.4 m

acceleration due to gravity (g) = 9.8 m/s^2

work done (wd) = ?

we can calculate the work done by the boy in pushing the chair using the law of law of conservation of energy

wd + mgh = (0.5 mVf^2) - (0.5 mVi^2) + (FF x d)

wd = (0.5 mVf^2) - (0.5 mVi^2) + (FF x d) - (mgh)

where wd = work done

m = mass

h = height

g = acceleration due to gravity

FF = frictional force

d = distance

Vf and Vi = final and initial velocity

wd = (0.5 x 54.5 x 6.9^2) - (0.5 x 54.5 x 1.4^2) + (41 x 12.4) - (54.5 X 9.8 X 2.1)

wd = 630.75 j

3 0

3 years ago

Two point charges exert a 5.00 N force on each other. What will the force become if the distance between them is increased by a

weeeeeb [17]

Answer:

force becomes one - ninth

Explanation:

According to Coulomb's law in electrostatics, two charges can exert a force of attraction or repulsion on each other which is directly proportional to the product of two charges and inversely proportional to the square of distance between them.

Here both the charges remains same but the distance is variable.

So, we can say that

$F \alpha \frac{1}{d^{2}}$ .... (1)

Where d be the distance between the tow charges

As the distance between two charges increases by factor of three, let the new force be F'.

$F' \alpha \frac{1}{9d^{2}}$ .... (2)

Divide equation (2) by equation (1), we get

$\frac{F'}{F}=\frac{d^{2}}{9d^{2}}$

$F'=\frac{F}{9}$

Thus, the force becomes one - ninth times the initial force.

6 0

3 years ago

5) When a substance changes its state, all BUT ONE of these statements is true That is A) Mass remains constant B) Only the form

expeople1 [14]

C) kinetic energy changes. Gas>liquid>solid

7 0

3 years ago