Hope this helps And here is the answer for you
Answer:
Answer:
r=\dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}r=
B
1
e
2Vm
Explanation:
Let m and e are the mass and charge of an electron. It is accelerated from rest through a potential difference V and are then deflected by a magnetic field that is perpendicular to their velocity. Let v is the velocity of the electron. It can be calculated as :
\dfrac{1}{2}mv^2=eV
2
1
mv
2
=eV
v=\sqrt{\dfrac{2eV}{m}}v=
m
2eV
When the electron enters the magnetic field, the centripetal force is balanced by the magnetic force as :
\dfrac{mv^2}{r}=evB
r
mv
2
=evB
r=\dfrac{mv}{eB}r=
eB
mv
or
r=\dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}r=
B
1
e
2Vm
So, the radius of the resulting electron trajectory is \dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}
B
1
e
2Vm
. Hence, this is the required solution.
Answer:
1.5 x 10¹⁸hz
Explanation:
Given parameters:
Wavelength = 2 x 10⁻¹⁰m
Unknown:
Frequency = ?
Solution:
To find the frequency, use the expression below;
V = f x wavelength
V is the speed of light = 3 x 10⁸m/s
f is the frequency
Now;
Insert the parameters
3 x 10⁸ = 2 x 10⁻¹⁰ x frequency
Wavelength = = 1.5 x 10¹⁸hz
C, they are transverse and travel at the speed of light
Answer:
14.0 cm
Explanation:
Draw a free body diagram of the block. There are three forces: weight force mg pulling down, elastic force k∆L pulling down, and buoyancy ρVg pushing up.
Sum of forces in the y direction:
∑F = ma
ρVg − mg − k∆L = 0
(1000 kg/m³) (4.63 kg / 648 kg/m³) (9.8 m/s²) − (4.63 kg) (9.8 m/s²) − (176 N/m) ∆L = 0
∆L = 0.140 m
∆L = 14.0 cm