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irakobra [83]
3 years ago
13

The state in which a star's gravitational collapse is balanced between gravity pushing inward and gas pressure pushing outward i

s called
Physics
2 answers:
Andrew [12]3 years ago
5 0
The relation between temperature and pressure is called the "equation of state of the gas". or "Hydrostatic equilibrium in ordinary star". Take for example a balloon, it will have a larger spherical shape, if the pressure inside exerted by the gas on a wall of a balloon balance the inward force exerted by the outside atmospheric pressure.  In a dying star which is being compressed by gravity, the gas is being squeezed so the molecules is moving rapidly, resulting to a very high temperature, and this provide a balance that counteract or balances the compressive force of gravity. The very high temperature inside the star is needed to balance the force of gravity, and it is provide by "nuclear fusion energy" or else the star would collapse under the force of gravity. Depending on the size or mass of the star, it will either become, a "neutron star" or a "black hole".                 
joja [24]3 years ago
4 0

Answer:  Hydro-static Equilibrium

Explanation:

A fluid in its stable rest state is said to have hydro-static equilibrium. A star is composed of gases mainly hydrogen and helium. It is huge in size and mass. It does not collapses under its own weight because of the pressure exerted outwards by the ongoing nuclear fusion reaction in its core which balances the gravitational force. Thus, a star maintains a state of hydro-static equilibrium.

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Even when shut down after a period of normal use, a large commercial nuclear reactor transfers thermal energy at the rate of 150
Phoenix [80]

Answer:

The temperature of the core raises by 2.8^{o}C every second.

Explanation:

Since the average specific heat of the reactor core is 0.3349 kJ/kgC

It means that we require 0.3349 kJ of heat to raise the temperature of 1 kg of core material by 1 degree Celsius

Thus reactor core whose mass is 1.60\times 10^{5}kg will require

0.3349\times 1.60\times 10^{5}kJ\\\\=0.53584\times 10^{5}kJ

energy to raise it's temperature by 1 degree Celsius in 1 second

Hence by the concept of proportionately we can infer 150 MW of power will increase the temperature by

\frac{150\times 10^{6}}{0.53584\times 10^{8}}=2.8^{o}C/s

5 0
3 years ago
Two wires are made of the same material. Wire 1 has length that is 1.35 times the length of wire 2 and diameter that is 0.91 tim
Oksi-84 [34.3K]

Answer:

1.117935:1

Explanation:

Since the wires are of the same material, they will have the same resistivity \rho.

The cross-sectional area of the of a wire is given by;

A=\pi\frac{d^2}{4}................(1)

where d is the diameter of the wire.

Also, the relationship between resistance R, cross-sectional area A and length l of a wire is given as follows;

\rho=\frac{RA}{l}..................(2)

Since the resistivity same for both wires, say wire 1 and wire 2, we can wreite the following;

\frac{R_1A_1}{l_1}=\frac{R_2A_2}{l_2}..................(3)

Hence from eqaution (3), the ration of wire 1 to 2 is expressed as;

\frac{R_1}{R_2}=\frac{l_1A_2}{l_2A_1}..................(4)

Given;

l_1=1.35l_2

\frac{R_1}{R_2}=\frac{1.35l_2A_2}{l_2A_1}\\\frac{R_1}{R_2}=\frac{1.35A_2}{A_1}.............(5)

We then use equation (1) to fine the ratio of the area A_1 to A_2

bearing in mind that d_1=0.91d_2

This ratio gives 0.8281. Substituting this into equation (5), we get the following;

\frac{R_1}{R_2}= 1.35*0.8281=1.117935

4 0
3 years ago
Read 2 more answers
Can someone help?? 3/5
ycow [4]

Answer:

Yes to answer is 3/5 of what

8 0
3 years ago
ONLY GIRLS THAT DO THIS PLEASE ANSWER my questions ONLY IF YOU ARE A GIRL QND DO THIS THO if your a guy please EXIT THIS QUESTIO
adoni [48]

Answer:

Here Are Some Tanning Bed Tips For Beginners To Help You Get The Most .Knowing your skin type before you tan can help you to do so safely and help . If you want to ensure you get a quality tan, you first need to be certain your . Obviously, if you wear a bathing suit, you'll get tan lines from the suit. Apply indoor tanning lotion evenly in a circular motion and over all areas of the body. Using the right skin care products is the best way to extend the life of your tan.  Note that lotions not made for indoor tanning can cause damage to tanning beds and don't help develop your tan. So what (if anything) should you wear? There are a lot of different views on this particular question, and it all comes down to one very simple answer: wear whatever you are comfortable in. If you wear your bathing suit every time, you will have tan lines that reflect that, but that's your choice.

Explanation:

7 0
3 years ago
Two small, identical metal balls with charges 7.0 µC and 14.0 µC are held in place 1.9 m apart. In an experiment, they are conne
Nostrana [21]

The new charge on 7.0 µC ball is 10.5 µC and the new charge on 14.0 µC ball is 10.5 µC.

The change in the electrostatic force after the experiment is 0.031 N.

The given parameters:

  • Charge on first metal ball, q1 = 7.0 µC
  • Charge on second metal ball, q2 = 14 µC
  • Distance between the charges, r = 1.9 m

<h3>Charge on each ball after experiment</h3>

After the experiment the charges will be at equilibrium, and the charge on each metal ball will be equal.

Q_t = q_1 + q_2\\\\Q_t = 7 \mu C + 14 \mu C\\\\Q_t = 21 \ \mu C

Q_1 = Q_2 = \frac{Q_t}{2} = \frac{21 \mu C}{2} = 10.5 \ \mu C

The new charge on 7.0 µC ball = 10.5 µC

The new charge on 14.0 µC ball = 10.5 µC

<h3>Change in electrostatic force</h3>

F_1 =  \frac{kQ_1Q_2}{r^2} \\\\F_1 = \frac{9\times 10^9}{1.9^2} (7 \times 10^{-6} \times 14 \times 10^{-6}) \ \\\\ F_1 =  0.244 \ N\\\\for \ new \ charges;\\\\F_2 =  \frac{kQ_1Q_2}{r^2} \\\\F_2 = \frac{9\times 10^9}{1.9^2} (10.5 \times 10^{-6} \times 10.5 \times 10^{-6}) \ \\\\ F_2 =  0.275 \ N\\\\\Delta F = F_2 - F_2\\\\\Delta F = 0.275 \ N \ - \ 0.244 \ N\\\\\Delta F = 0.031 \ N

Lear more about electrostatic force here: brainly.com/question/17692887

8 0
2 years ago
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