B. Velocity.
Momentum of a object = Mass * Velocity.
The momentum is a vector quantity and It has the same direction as the velocity.
Answer:
I think it is D but don't count on it
Answer:A)For open pipe
1stπ=484cm
2nd wavelength=161.3cm
3rd is=96.8cm
B)For closed pipe
1st wavelength=242cm
2nd=121cm
3rd wavelength=80.7cm
Explanation:
An open pipe produces a standing waves whose wavelength is related to it's length(length of pipe) by nL/4=π ,where n represent odd integers 1,2,3...
So the first note called fundamental note or 1st Harmonic is L=π/ 4,121=π/ 4
π= 121×4=484cm
Third harmonic,L=3π /4
So π= 4l/3=4×121/3=161.3cm
The 3rd wavelength is
Fifth harmonic=
π =4l/5=4×121/5=96.8cm
For a pipe open at one end and closed at the other also called closed pipe
Fundamental note is
2L/n= π where n=1,2,3....ie integers
First wavelength
π=2L=2×121=242cm
Second wavelength
π=L=121cm
Third is
π=2L/3=2×121/3=80.7cm
Answer:
Explanation:
Given
Sphere A has a net charge of +5 Q
Sphere B has a net charge of -3 Q
Sphere C has a net charge of 7 Q
When sphere B is touched to sphere A then charge is redistributed among the sphere such that charge on each sphere is
Now sphere A and B has charge Q
When sphere A is touched to sphere C
Net charge after removal
Now sphere A and C has 4 Q charge
Now sphere C and B is touched
Net charge on C and B is given by
At the end of process charge on sphere A is 4Q
Charge on B and C is 2.5Q
Answer:
116.7 Hz
Explanation:
Let there are two wires A and B.
Tension in wire A = T
Tension in wire B = 2T
Length of wire A = L
Length of wire B = 2L
fundamental frequency in wire A, fA = 330 Hz
let the fundamental frequency in wire B is fB.
The formula for the fundamental frequency is given by
where, μ is the mass per unit length
mass per unit length of wire A = Area of wire A x density
mass per unit length of wire B = Area of wire B x density
So,
fB = 330 / 2.828
fB = 116.7 Hz
Thus, the frequency in the second wire is 116.7 Hz.